[Resolved] Strange class behavior

schampeau

I am trying to build my first PHP class, and have encountered some strange behavior, which I have distilled into the following test class:

class TestClass {
var $var1 = '';
var $var2 = '';
var $var3 = '';

function TestClass($var1X, $var2X, $var3X) {
$this->$var1 = $var1X;
$this->$var2 = $var2X;
$this->$var3 = $var3X;
}

function getVar1() {
return $this->$var1;
}

function getVar2() {
return $this->$var2;
}

function getVar3() {
return $this->$var3;
}

function output() {
echo $this->$var1.' ';
echo $this->$var2.' ';
echo $this->$var3.' ';
echo ' ';
echo $this->getVar1().' ';
echo $this->getVar2().' ';
echo $this->getVar3().' ';
}
}

When I execute the following code:

$test = new TestClass('steve', 'was', 'here');
$test->output();

I get the following output:

here
here
here

I have looked at a number of PHP class examples, and am pretty sure I am following the rules, but there must be some simple thing I'm missing.

Thanks,
Steve C.

ZibingsCoder

All you need to do is take out the dollar signs like I've shown below.

class TestClass { 
var $var1 = ''; 
var $var2 = ''; 
var $var3 = ''; 

function TestClass($var1X, $var2X, $var3X) { 
$this->var1 = $var1X; 
$this->var2 = $var2X; 
$this->var3 = $var3X; 
} 

function getVar1() { 
return $this->var1; 
} 

function getVar2() { 
return $this->var2; 
} 

function getVar3() { 
return $this->var3; 
} 

function output() { 
echo $this->var1.'<br>'; 
echo $this->var2.'<br>'; 
echo $this->var3.'<br>'; 
echo '<br>'; 
echo $this->getVar1().'<br>'; 
echo $this->getVar2().'<br>'; 
echo $this->getVar3().'<br>'; 
} 
}

sanam

You have wrong syntex while using variables. If you change error reporting to all , you will see your errors. On development enviroment you should use all error reporting. Check this link for more details.
http://ca2.php.net/error-reporting

Error in code:

$this->$var1 = $var1X;

should be like this:

$this->var1 = $var1X;
No dollar sign in front of var

change it all the places where you are using
$this->$var1
$this->$var2
$this->$var3

with

$this->var1
$this->var2
$this->var3

schampeau

I knew it had to some bonehead thing like that.

Many thanks!

I'll definitely check out the error reporting link.