[Resolved] image buton ???? help !!

anne

Hi..
I wanted to use an image as my form's submit button to send data to '$PHP_SELF',
but it didn't work unless I use a type=submit button.
Can anyone explain why I can't use the image as my button?
And how can I solve this ?

This is a part of my code :

     echo "<form action='$PHP_SELF' method=post>";
      .
      .	
     echo "<input type=hidden name=k value='$k'>";
     echo "<input  type=image  src=images/del.gif name=del>";
     echo "</form.";

Thank u 🙂

Mordecai

1) No such thing as $PHP_SELF. You can read why here.
2) You need to use quotes around anything that carries non alpha-numeric characters in HTML. That means [FONT=courier new]echo "<input type=image src=images/del.gif name=del>";[/FONT] does not work. Instead, use [FONT=courier new]echo "<input type=image src=\"images/del.gif\" name=del>";[/FONT]. It also won't hurt to put them around everything.
3) You don't have a </form>, which is required. </form. won't cut it.

Hope that helps.

shorty114

So the final code will be:

echo '<form action="' . $_SERVER['PHP_SELF'] . '" method="post">'; 
     echo '<input type="hidden" name="k" value="'.$k.'">'; 
     echo '<input  type="image" src="images/del.gif" name="del">'; 
     echo "</form>";

Frederick

Instead of using name=\"del\" in your button, place it in a hidden tag
. "<input type=\"hidden\" name=\"del\" value=\"1\">\n"

if (isset($_POST['del'])) {
    // process
} else {
    echo "<form action=\"" . $_SERVER["PHP_SELF"] . "\" method=\"post\">\n"
    . "<input type=\"hidden\" name=\"del\" value=\"1\">\n"
    . "<input type=\"hidden\" name=\"k\" value=\"$k\">\n"
    . "<input  type=\"image\" src=\"images/del.gif\">\n"
    . "</form>\n";
}

anne

Thank you so much... 😃

I'm a few days late reviewing the replies..but I still am sooooooo happy. I doubt you guys will read this, but nevertheless.
Thank you, thank you, thank you.

luv you guys !!!