Replace only second occurrence

Mandakins

I'm trying to add an image tag in a paragraph depending on which paragraph the user wants it to appear in.

For example, if they want it in the second paragraph, I'd replace with <img src = 'blahwhatever'>.

Can I use preg_replace to do this? Like so:

preg_replace("","$imagelink", $content, $pnumber);

OR - if the paragraph number is 2, will it replace both the first AND second occurrences? If so, how do I make it start and end with the paragraph number that is passed?

Thanks!

xblue

Hi Mandakins,

I don't think there is a build-in way to provide some kind of "offset" argument in addition to the limit argument.

What I could think of:
a) limiting to n, then changing everything back limiting to n-1
(probably not a good approach, it was just the first one)

b) alternatively, you could split it at , then only modify the part you want, and implode it again.

c) or it may be possible to include all these "unwanted" paragraphs within in the match and reuse them in the replacement argument (make sure to match ungreedy and set the dot-match-all modifier), like

preg_replace("/((<p>.*?){n})<p>/s","$2<p>$imagelink", $content, $pnumber);

with n being the number of paragraphs that are to be unchanged

btw. you don't mean to use <> as delimiters, do you?