[Resolved] Find 2nd Wednesday of every month?

[[deleted]]

OK, it is Friday and I must not be thinking clearly. I am trying to figure out how to find the date for the 2nd Wednesday of the month. If today is past that date, then get the 2nd Wednesday of next month. Anyone done this before? Google didn't really return anything.

TIA,

[[deleted]]

Surely someone here has done this?

[sidney]

 function dayofsecondweek($date,$weekday)
	{
	list($year,$month,$day)=explode('-',$date);
	$wed=0;
	$cday=1;
	while($cday<15)
		{
		$mtime=date('w',mktime(0,0,0,$month,$cday,$year));
		if($mtime==$weekday)
			{
			$wed++;
			if($wed>1 && $day<=$cday)
				return date('Y-m-d',mktime(0,0,0,$month,$cday,$year));
			elseif($wed>1 && $day>$cday)
				{
				$day=0;
				$cday=1;
				$wed=0;
				$month++;
				}
			else 
				$cday+=6;
			}
		$cday++;
		}
	}
//feed function date format yyyy-mm-dd and day of week 0 =sunday through to 6 =saturday
echo dayofsecondweek(date('Y-m-d',time()),3); 

[Weedpacket]

Could probably be simplified; but this is the first thing I came up with that worked:

function second_wednesday($timestamp)
{
	list($year,$month,$date)=explode(':',date('Y:n:j',$timestamp));
	$second_wednesday = strtotime('2nd Wednesday', mktime(0,0,0,$month,1,$year));
	if($second_wednesday<mktime(0,0,0,$month,$date,$year)) // Try next month (Maybe you'll want "<=", here)
		$second_wednesday = second_wednesday(mktime(0,0,0,$month+1,1,$year));
	return $second_wednesday;
}

$timestamp = mktime(0,0,0,10,24,2004);
$second_wednesday = second_wednesday($timestamp);
echo date('Y-m-d',$second_wednesday);

[[deleted]]

Sorry for the double post. Thanks to all who responded.