Include Problem

[edpudol]

I have problem calling variable from my other server.

I created a script from my other server that I include at the second server, the problem is that I can't access the content of the variable:

I use this code for my second server:

include ('http://www.myserver1.com/call.php');
echo "$Server1Var";

The $Server1Var is stored at server 1 and with the value $Server1Var = "Content".

How could I possibly access the data stored in the database?

[yelvington]

It doesn't work that way.

When you include() a remote file from a PHP server, you do NOT include PHP code. Instead, you include the output result of the PHP process on the remote server, which presumably is Plain Old HTML.

As the manual says:

If "URL fopen wrappers" are enabled in PHP (which they are in the default configuration), you can specify the file to be included using a URL (via HTTP or other supported wrapper - see Appendix L for a list of protocols) instead of a local pathname. If the target server interprets the target file as PHP code, variables may be passed to the included file using a URL request string as used with HTTP GET. This is not strictly speaking the same thing as including the file and having it inherit the parent file's variable scope; the script is actually being run on the remote server and the result is then being included into the local script.

[edpudol]

How could I make possible to call the variable stored in remote server? Could you please give me sample how to do it? I am newbie in PHP so I am not yet familiar how to do this

thanks