Thanks for the quick response
$Picture is where the path from the form is stored in the db
This is the code I used
$file = $Picture
echo "<td width=7% align=center>"."<img src="$file" alt="my picture"></img> </td>";
But it says
Parse error: syntax error, unexpected T_VARIABLE, expecting ',' or ';'
on the line that my echo is on Am i just doing some simple thing wrong