Help with txt line number and PHP?Something

Reggie35

Hi all,

I have recently started with php and I found it to be a great scripting language, at least if one can figure it out 😃

Well my problem is that is that I want to call a link on the same page where I am at. I want to generate links within a loop from the line counts in a txt file, creating the numbers as it goes like i.e.

index.php?ID=1 //Line 1
index.php?ID=2 //Line 2
index.php?ID=3 //Line 3
........and so on.

When I click the link it should get the line number from the ID value, i.e.

index.php?ID=3 //Get line 3

Any ideas and help will be greatly appreciated. TIA.

Shrike

You can read an entire file line by line into an array using the function [MAN]file[/MAN]. It's easy from there to display the relevant line.

Reggie35

Thanks, I appreciate your help. I manage to loop the content in the file, my big thing is to actually call the actual line provided by its integer value. Here's my loop

for($i=0;$i<count($reOut);$i++){
	$x = $x + 1;    

	$info = "<a href=\"index.php?ID=$x\">";

    //Get all the lines
	if ($reOut[$i] > NULL )
	echo "$info<img src=\"ipimg/log.gif\" width=\"13\" height=\"13\" border=\"0\" alt=\"More info about ".$reOut[$i]."\"></a>";	

   }

How do I read the line ID=$x and display it on the same page? Thanks again.

gufmn

Originally posted by Reggie35
Thanks, I appreciate your help. I manage to loop the content in the file, my big thing is to actually call the actual line provided by its integer value. Here's my loop
for($i=0;$i<count($reOut);$i++){
	$x = $x + 1;    

	$info = "<a href=\"index.php?ID=$x\">";

    //Get all the lines
	if ($reOut[$i] > NULL )
	echo "$info<img src=\"ipimg/log.gif\" width=\"13\" height=\"13\" border=\"0\" alt=\"More info about ".$reOut[$i]."\"></a>";	

   }
How do I read the line ID=$x and display it on the same page? Thanks again. [/B]

if (isset($_GET['ID'])){
    $id = $_GET['ID'];
}

Reggie35

Bingo! That did the trick, thanks gufmn 🙂