Help with Gallery Script

[jayo]

I have this gallery code, which I've modify to fit my site.. ITs from
http://www.jeroenwijering.com/?itm=9

Anyway, the little piece of code below displays the different galleries links..

It originally displayed the links like so:

Gallery 1
Gallery 2
Gallery 3

But I modified the code by adding the array_reverse bit so it displays like this now:

Gallery 3
Gallery 2
Gallery 1

The problem is that now thats the links are reversed, it links wrong,

Gallery 3 - link to Gal 1
Gallery 2 - link to Gal 2
Gallery 1 - link to Gal 3

I want to fix this, is there somethign wrong below I need to fix?

Anyway,

// links display

$gal = $HTTP_GET_VARS["gal"];
$pic = $HTTP_GET_VARS["pic"];

$n = 1;
$links = array();

$fp = fopen("links.txt", "r");
while (!feof($fp)) {
$link = fgets($fp, 500);
if($link) {
$links[$n] = rtrim($link);
$n++; } }
fclose($fp);

$links = array_reverse($links);

for ($i=1; $i<=sizeof($links); $i++) {
echo "<a href=?gal=".$i.">".$links[$i]."</a>";
if ( $i<=(sizeof($links)-1)) { echo " <br> "; } }

[bodzan]

Delete line :
$links = array_reverse($links);

and change the for loop to:

for ($i=sizeof($links); $i>=1; $i--) {
echo "<a href=?gal=".$i.">".$links[$i]."</a>";

This way you avoid sorting an array which might be causing your troubles and still to get it the way you want it i.e reverse.

[jayo]

Thanks that seems to work,

with this

// links display

$gal = $HTTP_GET_VARS["gal"];
$pic = $HTTP_GET_VARS["pic"];

$n = 1;
$links = array();

$fp = fopen("links.txt", "r");
while (!feof($fp)) {
$link = fgets($fp, 500);
if($link) {
$links[$n] = rtrim($link);
$n++; } }
fclose($fp);

for ($i=sizeof($links); $i>=1; $i--) {
echo "<a href=?gal=".$i.">".$links[$i]."</a>";
if ( $i<=(sizeof($links)-1)) { echo " <br> "; } }

There is one problem though the gallery links input is:

Gallery4Gallery3
Gallery 2
Gallery 1

after gallery 4 should be a <br>

Also, one other thing..
If you go to the index.php for the gallery.. It always start with the earliest gallery, which is Gallery 1, instead of 4.. meaning that gallery's 1 1st photo shows instead of the newest gallery which is 4 or if I add a 5th gall, that photo should show..

SHould anything with this code below be changed to get that effect

// photo display

if (!$gal) { $gal = 1; }
if (!$pic) { $pic = 1; }
$dir= "gallery".$gal;
@$d = dir($dir);

if ($d) {
while($entry=$d->read()) {

$entry = preg_replace("/ /","%20",$entry);
$pos = strpos (strtolower($entry), ".jpg");
if (!($pos === false)) {

$arr_pic[] = $dir."/".$entry; } }
$d->close(); }

@sort ($arr_pic);

$total = sizeof($arr_pic);
echo "<img src=".$arr_pic[$pic-1]." border=1 width=350 height=263>";

[bodzan]

...for the first problem, the line:

if ( $i<=(sizeof($links)-1)) { echo " <br> "; } }

will put an <br> after all the links except the first one so I'd put:

if ( $i>=2) { echo " <br> "; } }

so it will print <br> after all except the last one.

For the second problem:

if (!$gal) { $gal = 1; }
if (!$pic) { $pic = 1; }
$dir= "gallery".$gal;
@$d = dir($dir);

@sort ($arr_pic);
$total = sizeof($arr_pic);
echo "<img src=".$arr_pic[$pic-1]." border=1 width=350 height=263>";

I don't see that you gave any order that it should be the last picture shown. In fact you gave the direct oposite with this line
if (!$pic) { $pic = 1; }

which does the opposite i.e. sets variable $pic to 1 and then your code will be:
echo "<img src=".$arr_pic[1-1]." border=1 width=350 height=263>";

and thus the first pic in the array wil be shown.

Try doing it the opposite way i.e. setting the $pic to be the last one (for example 5)...

[jayo]

Originally posted by bodzan
For the second problem:

if (!$gal) { $gal = 1; }
if (!$pic) { $pic = 1; }
$dir= "gallery".$gal;
@$d = dir($dir);

@sort ($arr_pic);
$total = sizeof($arr_pic);
echo "<img src=".$arr_pic[$pic-1]." border=1 width=350 height=263>";

I don't see that you gave any order that it should be the last picture shown. In fact you gave the direct oposite with this line
if (!$pic) { $pic = 1; }

which does the opposite i.e. sets variable $pic to 1 and then your code will be:
echo "<img src=".$arr_pic[1-1]." border=1 width=350 height=263>";

and thus the first pic in the array wil be shown.

Try doing it the opposite way i.e. setting the $pic to be the last one (for example 5)... [/B]

Man, I really appreciate your help!! I don't fully understand, what I should do for the second problem

Heres the link to my gallery
http://www.ballerstatus.net/gallery/index.php

if you notice the pic being shown is the first pic from Gallery 1, what I want it to do is always show the first pic of the newest gallery, for instance right now, the pic shown would be the 1st pic from the 4th gallery.. If I add a 5th gallery, the 1st pic from the 5 gall should be shown, or if a s6th gallery, then so on and so on..

What should I change from this the below code to make this happen:

if (!$gal) { $gal = 1; }
if (!$pic) { $pic = 1; }
$dir= "gallery".$gal;
@$d = dir($dir);

if ($d) {
while($entry=$d->read()) {

$entry = preg_replace("/ /","%20",$entry);
$pos = strpos (strtolower($entry), ".jpg");
if (!($pos === false)) {

$arr_pic[] = $dir."/".$entry; } }
$d->close(); }

@sort ($arr_pic);

$total = sizeof($arr_pic);
echo "<img src=".$arr_pic[$pic-1]." border=1 width=350 height=263>";

[bodzan]

I understood what you want to do just now.

instead of sort() which sorts an array from lowest to highest you should use rsort() which does the opposite, in line:

@sort ($arr_pic);

[jayo]

Originally posted by bodzan
I understood what you want to do just now.

instead of sort() which sorts an array from lowest to highest you should use rsort() which does the opposite, in line:

@sort ($arr_pic);

Cool, I tried it and what it did was just show the last pic of the 1st gallery on the index.php page..

What I want is for it to show the 1st pic of the last gallery added.. which is gallery 4 or 5 if I was to add the 5th.. Each gallery are photos that are store in folders in this directory. What you think man?

[bodzan]

Sorry, again...

Now I understand! (I hope this time for real)...

Return to the sort. And change this line of code:

if (!$gal) { $gal = 1; }

with:

if (!$gal) { $gal = 4; }

Instead of 4 (which is the number of the last gallery at present but it won't be) you might want to use some dinamic reading i.e the same way you show the links on the right just to show one - latest.

[jayo]

Originally posted by bodzan
you might want to use some dinamic reading i.e the same way you show the links on the right just to show one - latest.

HOw would I do that?

[bodzan]

on the right side of the page now there is a listing of four links:
Gallery 4
Gallery 3
Gallery 2
Gallery 1

If you display it dinamically in some way via PHP show me the code and I'll help you.

If you do this by hand, then just use the way I showed you in my previous post.

[jayo]

Originally posted by bodzan
on the right side of the page now there is a listing of four links:
Gallery 4
Gallery 3
Gallery 2
Gallery 1

If you display it dinamically in some way via PHP show me the code and I'll help you.

If you do this by hand, then just use the way I showed you in my previous post.

well the links on the site are generated by that original code I had problems with:

// links display

$gal = $HTTP_GET_VARS["gal"];
$pic = $HTTP_GET_VARS["pic"];

$n = 1;
$links = array();

$fp = fopen("links.txt", "r");
while (!feof($fp)) {
$link = fgets($fp, 500);
if($link) {
$links[$n] = rtrim($link);
$n++; } }
fclose($fp);

for ($i=sizeof($links); $i>=1; $i--) {
echo "<a href=?gal=".$i.">".$links[$i]."</a>";
if ( $i>=2) { echo " <br> "; } }

THe words GALLERY 1 and so on are in a links.txt file,, with just the words, no code.. If it is a big hassle its ok.. You've already helped me so much!

[bodzan]

... read this file in order to figure out which gallery is the latest i.e:

$fp = fopen("links.txt", "r");..this line opens file for reading

while (!feof($fp)) {//line will read all through file untill the end of file is found
$link = fgets($fp, 500);//this line reads the line 500 charsacters of it
if($link) {//for every link that it reads it will write them down
$links[$n] = rtrim($link);//this line deletes the end line characters like \n\r and such
$n++; } }

This way you get an array links where [0] is first link in the file...

To show the last line just do this:

echo count($links);

This value should be the right one if the data in the file is like
Gallery 1
Gallery 2
Gallery 3
Gallery 4
Gallery 5

i.e there is 5 lines of text so the last gallery is 5th and there will be 5 elements in the array $links

[bodzan]

... read this file in order to figure out which gallery is the latest i.e:

$fp = fopen("links.txt", "r");..this line opens file for reading

while (!feof($fp)) {//line will read all through file untill the end of file is found
$link = fgets($fp, 500);//this line reads the line 500 charsacters of it
if($link) {//for every link that it reads it will write them down
$links[$n] = rtrim($link);//this line deletes the end line characters like \n\r and such
$n++; } }

This way you get an array links where [0] is first link in the file...

To show the last line just do this:

echo count($links);

This value should be the right one if the data in the file is like
Gallery 1
Gallery 2
Gallery 3
Gallery 4
Gallery 5

i.e there is 5 lines of text so the last gallery is 5th and there will be 5 elements in the array $links

so just use this:

if (!$gal) { $gal = count($links); }

[jayo]

Originally posted by bodzan
... read this file in order to figure out which gallery is the latest i.e:

$fp = fopen("links.txt", "r");..this line opens file for reading

while (!feof($fp)) {//line will read all through file untill the end of file is found
$link = fgets($fp, 500);//this line reads the line 500 charsacters of it
if($link) {//for every link that it reads it will write them down
$links[$n] = rtrim($link);//this line deletes the end line characters like \n\r and such
$n++; } }

This way you get an array links where [0] is first link in the file...

To show the last line just do this:

echo count($links);

This value should be the right one if the data in the file is like
Gallery 1
Gallery 2
Gallery 3
Gallery 4
Gallery 5

i.e there is 5 lines of text so the last gallery is 5th and there will be 5 elements in the array $links

Im not a coder by any means, man.. So Ill just manually add that number into the solution mentioned in your other post.. I REALLY appreciate you help!! Most people wont even help you and you lent a helping hand, god bless!

[bodzan]

...everyone started the same...