[Resolved] 1 line systen error dealing with echo and variables?

maximum-php

Hey,

I have a loop that will execute X amount of times. In that loop I increment a variable and echo one line.

echo "$info[$i] <input type=\"checkbox\" name=\"$info[$i]\" value=\"1\">";

The problem part of that echo seems to be with how i'm trying to echo that array[variable as index]

$info[] = an associative array from a mysql fetch.

$i = a numerical number 1-99.

I've attempted varations on the syntax such as not placing the periods before and after the $info[$i]. i've also tried $info['$i'] ext.

I was able to accomplish something like this in ASP, I would assume its possible in PHP?

Anyways any suggestions ext, would be appreciated.

P.S.

I'm assuming that maybe the reason its not working is that when PHP parses that line, It does not look at my syntax such as $info[1] $info[2] ext, It ends up trying to display $info[$i], as if $i was the INDEX KEY?? and not the value of $i which is 1?? anyways i'm confused..

LarsLai

hi!
if i have a look at your syntax highlighting: could it be you just set the quotes wrongly? try this:

echo $info[$i] . "<input type=\"checkbox\" name=\"" . $info[$i] . "\" value=\"1\">";

PallaviDalvi

i tried the line of code and it worked perfectly fine for me. cud u tell what error description(if any) u get? or maybe the final HTML created for the checkboxes?

czambran

try this:

echo "{$info[$i]} <input type=\"checkbox\" name=\"$info[$i]\" value=\"1\">";

See the braces I put around the array, that should fix your problem.

maximum-php

Sorry for delay in feedback, was not able to get home and test out the suggestions until now.

While playing with it now, i've since then narrowed the issue down to the fact $info[0] = nothing??

So now i'm stumped on a few things and i guess i need clarification.

On a previous page I used this chunk of code -

$info = mysql_fetch_array($query, MYSQL_ASSOC);[code=php]

and

[code=php]foreach ($info as $key => $value) {
	if ($value == '1') {
		$key = ucfirst($key);
		echo "<a href=\"$key.php\" style=\"text-decoration:none\" target=\"main\">$key</a><br>";
        }
}

Which gave me the result I wanted,, It gave me the Fields name of my database instead of the Value's in the rows of that field.

Now I assumed simply using the same

$info = mysql_fetch_array($query, MYSQL_ASSOC);[code=php]

and

[code=php] echo $info[0]; [code=php]

would give me the FIELD name not the first item underneath that FIELD??

where did I make my mistake??   Hopefully it makes sense

Thx..

PallaviDalvi

in this loop

foreach ($info as $key => $value) {
    if ($value == '1') {
        $key = ucfirst($key);
        echo "<a href=\"$key.php\" style=\"text-decoration:none\" target=\"main\">$key</a><br>";
        }
}

$key will give field name and $value will give value stored for that field....and here

$info = mysql_fetch_array($query, MYSQL_ASSOC);
echo $info[0];

the value for the first field will be echoed ...not the feildname.... i am not exactly sure WHAT u want to print...fieldname or the value... but i guess now u are in a position to decide which one to use.

maximum-php

Cool thx, so last question.

How do I go about printing the FIELD name without using a foreach loop to get access to $KEY? I simply want to, pull the results from the MySQL Query with mysql_fetch_array($var, MYSQL_ASSOC); Then with one line, print just one Field. Is there a way to accomplish that without having to use

foreach ($var as $key => $value)?? can I access $key some otherway, or anything like that??

Thx,

PallaviDalvi

you cud use mysql_field_name or mysql_list_fields() to get the field names instead of the values.

maximum-php

Hey thanks, mysql_field_name worked great. Appreciate all the help.

No longer confused ,