"if" question

[cedricm]

Hello everybody,

I have a problem with a if sentence:

$flag_adm_cat = "7,9";
$flag_adm_cat_0 = explode (",", $flag_adm_cat);
$flag_adm_cat_count = count(explode (",", $flag_adm_cat));
$tst_count= 0;
$check_count ="(";
while ($tst_count != $flag_adm_cat_count){
$check_count .= "($flag_adm_cat_0[$tst_count] == $flag_adm_cat_check)";
$tst_count++;
if ($tst_count != $flag_adm_cat_count) {
$check_count .= " or ";
}
}
$check_count .= ")";
.................
Result example:
((7 == 63) or (9 == 63))

Then:
if ($check_count) {
...........
}

Result example:
if ((7 == 63) or (9 == 63)) {
echo"Working";
}
The $check_count isn't reconize by the if()
The $check_count value is the correct
But it doesn't work at all? Any Idea? Thanks

When I replace the $check_count by ($flag_adm_cat_0[0] == $flag_adm_cat_check) or ($flag_adm_cat_0[1] == $flag_adm_cat_check) it works well!

At this the if content isn't reconize.

What should I have to do for the if() works with?
How to do

[cedricm]

Please Help wanted

[TheDefender]

Be Patient. In addition to you not using the PHP tags in your post, thus making it hard to read your code, your English is not very good, so that added to the difficulty of your post, but here goes:

// Change:
if ((7 == 63) or (9 == 63)) { 
echo"Working"; 
} 
// To:
if ((7 == 63) || (9 == 63)) { 
echo"Working"; 
} 

[chintupintu03]

Hello cedricm,

As suggested by "TheDefender", use "||" instead of "or".

Also, you mentioned in your query that the "IF" statement works well with "($flag_adm_cat_0[0] == $flag_adm_cat_check) or ($flag_adm_cat_0[1] == $flag_adm_cat_check)" and not with "$check_count ", please check by using "echo" command after your while loop finishes, whether the string formed for "$check_count" is same as what you are directly using in the "IF" statement.

After your "$check_count .= ")"; "
add one more line for testing as echo $check_count ;

You try to use these types of checking steps, so as to solve these kind of problems yourself. ( in the above case, while loop is giving proper output as required or not.)

[cedricm]

Hello everybody and thank you for your answer.

I have tested your solutions but the problem is always the same.

The if sentencs cannot reconize the

$check_count

as a sentence.

$check_count should be replaced by the sentence

($flag_adm_cat_0[0] == $flag_adm_cat_check) or ($flag_adm_cat_0[1] == $flag_adm_cat_check)

I have inserted an

echo"$check_count"

and the result give: (7==63) || (9==63) AND (2 == 2)

It seems tha the if statement cannot use this result correctly.

if ((7==63) || (9==63) AND (2 == 2)) {...}

doesn't work.

Full script:

$flag_adm = "2"; 
$flag_adm_cat = "7,9"; 
// Special administration
$flag_adm_cat_check = getparentlink_main($id_sub_cat,$description_main);
        $flag_adm_cat_0 = explode (",", $flag_adm_cat);
        $flag_adm_cat_count = count(explode (",", $flag_adm_cat));
        $tst_count= 0;
        //$check_count ='(';
        while ($tst_count != $flag_adm_cat_count){
        $check_count .= '(';
        $check_count .= $flag_adm_cat_0[$tst_count];
        $check_count .= '==';
        $check_count .= $flag_adm_cat_check;
        $check_count .= ')';
        $tst_count++;
        if ($tst_count != $flag_adm_cat_count) {
        $check_count .= ' || ';
        }
        }
        //$check_count .= ")";
        $check_count .= "AND ($flag_adm == 2)";

echo"$check_count";

 if ($check_count) {
        echo"Working";
        }

Thanks in advance

[Weedpacket]

It's because $check_count is a string; and all strings test as "true" unless they're empty. PHP doesn't care that the text inside the string looks a bit like PHP code or not (if it did, just about every possible string would cause a parse error).

There must be a better approach to what you want than what you're trying, but since I don't really understand what you're trying to do I can't suggest much of an improvement.

You could change $check_count so that it starts with "return " and ends with ";", and then write if(eval($check_count)). But like I said, your whole approach needs to be thought about again. If eval is the answer, then the question is probably wrong.

[cedricm]

Hello,

The question is:

if ($check_count) { echo"test"; }

How to do for the if work.

Where

$check_count = "$flag_adm_cat_0[0] == $flag_adm_cat_check";

Thanks

[herve]

I'm not sure but the eval() function might help you :

http://www.php.net/manual/en/function.eval.php

[Weedpacket]

Originally posted by herve
I'm not sure but the eval() function might help you :

http://www.php.net/manual/en/function.eval.php

But like I said; if that's the answer then it's probably the wrong question. There must be a better approach to whatever it is that is to be done.

$check_count = false;
for($tst_count=0; $tst_cout<$flag_adm_cat_cont; $tst_count++)
{ // Why don't people use for loops any more?
	if($flag_adm_cat_0[$tst_count] == $flag_adm_cat_check)
	{
		$check_count = true;
		break;
		// It's going to stay true for the
		// rest of the loop anyway.
	}
}
// Now for that AND clause
$check_count = $check_count && ($flag_adm==2);

That could be tidied up more, but it's fairly close to the intent of the original (I think). What appears to have happened here is a confusion between PHP and SQL.

[herve]

Originally posted by Weedpacket
But like I said; if that's the answer then it's probably the wrong question. There must be a better approach to whatever it is that is to be done.

I completely agree with you on this point 🙂

(but I like to help imaginative people 😉 )

[cedricm]

Thank you all for the answer, I have tested all solutions and the last one works perfectly, thanks again