img src tag with php

evmace

Is there anything special I need to do to allow this to work:

in a php document, I have an <img src="file.php?id=3">

It seems that the document doesn't know to send that variable through file.php

Anything special I need to do?

Thanks.

tsinka

Hi,

a guess:

Use $_GET['id'] instead of $id.

Post the script if that doesn't work.

Thomas

evmace

Here's what I have...(I posted this yesterday too to no avail):

index.php3:

thumb.php3:

<?php
$db = mysql_connect("localhost","xxxxx","xxxxx");
mysql_select_db("xxxxx",$db);
$sql="SELECT thumb FROM gallery WHERE id=".$_GET['id'];
$query=mysql_query($sql,$db);
while($row=mysql_fetch_array($query))
{
$thumb=$row["thumb"];
echo "thumbs/$thumb";
}
?>

The end result I want is for thumb.php3 to place an image's file name into the img src tag.

Am I doing this correctly?

tsinka

Ok,

the browser expects the image data.
Have a look at Example 3 in the manual.

Fetch the filename and either passthrough the image data of that image or the data of a default image if the file doesn't exist.

Thomas

evmace

But I haven't stored any image data in my database...just file names.

Isn't there a way to just have the php script plug the file name into my html?

sidney

Originally posted by evmace
Here's what I have...(I posted this yesterday too to no avail):

http://www.phpbuilder.com/board/showthread.php?s=&threadid=10287375

as i showed in that thread you need to rediect to the location of the image

and as i tried to point out in above thread i dont think your returning any results from the db

as what you had should work with the header as i use it my self to place image links from db in to staic html

also the <img src="thumb.php3?id=1"> would neever change

tsinka

I should've been more specific 🙂

Two ways:

get the filename and print the image tag with the image filename. PHP is a server side language. With the code you posted the browser tries to get the image data but the image script just prints the filename and not any image data. You can't change the HTML code if it has been sent to the browser already.

echo "<img src=\"thumbs/$thumb\">";

fetch the filename, check if the file exists, send a matching Content-Type header, open the file (stored on the disk) and send the image data to the browser as shown in the example.

Thomas