Change array value at run time

[joe2]

Hi,

I want to print a drop down of the number at the run time basis on certain calculation.

print "<table width='97%' border='0'>
<tr><td>Date Range ". $checkin. " to ". $checkout ."</td></tr>";
$room_type_arr=array();
$vac_arr=array();
while ($row_room=mysql_fetch_array($result_room)) {
$sql_vacant="SELECT * FROM roomtype WHERE roomtype='" . $row_room['type_of_rooms'] ."' AND idhotel=".$hotelid;
$result_vacant=mysql_query($sql_vacant,$link);
$row_vacant=mysql_fetch_array($result_vacant);

						$vacant=$row_vacant['numberofroom']-$row_room['filledroom'];
						$vac_arr[]=$vacant;
				  	if (!in_array($row_room['type_of_rooms'],$room_type_arr)){

			print	"<tr>
						<td class='text' >Types of rooms : ". $row_room['type_of_rooms'] . 
						  "<input name='rdoRoomType' type='radio' value='room_type'>
	  					</td>
					 	 <td >Number of rooms&nbsp;		    <select>
					    <option value='1'>1</option>
	    				</select></td>
					</tr>";	
					$room_type_arr[]=$row_room['type_of_rooms'];

					} // end of if to check , whether the room type is different
					}  // end of while; 
					print_r($vac_arr);
		  print "</table>";

I am storing vacant record in array $vac_arr. But it is storing value for all type of room.
If there is more then one type of room then this , how can i print it with each room type.

Thanks in advance.