[Resolved] $_GET array with more than 1 value per name

djwiltsh

I have a form that includes a multiple selection box, where you can click on more than one item and they are all selected. When the form is submitted, I get a query string similar to the following:

multiSelect=1, multiSelect=2, multiSelect=3... etc

What I need to do is for each value of multiSelect, add a record to a mysql database.

My question is, how can I loop through each value of multiSelect?

I have thought about reading the whole $_GET array into a string using the standard foreach loop method but this seems a bit clunky.

Thanks

Daniel

devinemke

a simple example (could be used for GET or POST):

<?
if (!isset($_POST['submit']))
{
	echo '<form action="" method="POST">
	<select name="numbers[]" size=5 multiple>
	<option>one
	<option>two
	<option>three
	<option>four
	<option>five
	</select><br>
	<input type="submit" name="submit" value="submit">
	</form>
	';
}
else
{
	if (isset($_POST['numbers']))
	{
		echo 'you selected the following '  . count($_POST['numbers']) . ' number(s):<br><br>';
		foreach ($_POST['numbers'] as $value)
		{
			echo $value . '<br>';
		}
	}
	else {echo 'you did not select any numbers';}
}
?>

surferdave

I am doing the same but using post. I am having major problems.
When I set the form to get so I can see the variables I see
mybox=value1
mybox=value2

so I know the multiselect box is working . but the problem lies when I try to get the data out. When I do
$count=count($_POST['mybox']);
echo "count is ".$count;
It always just returns the last item selected no matter how many items I select

this is the box code

what am I doing wrong

devinemke

look closely at my original example above.
in your code you need to change this:

<select name="myBox"

to this:

<select name="myBox[]"

surferdave

always the little stuff that gets you