[Resolved] static produces parse error

ppowell

                global $section;
		if (!isset($keyword)) static $keyword = $_REQUEST["${section}_search_keyword"];

The following produces a parse error, and I am stumped as to why, and of course can't find anything online, even in the PHP manual, that addresses this http://us2.php.net/language.variables.scope#static

This is breaking the entire application so I can't move further

Thanx
Phil

chyan

$REQUEST["${section}search_keyword"];

it's because wrong use of "{}"

ppowell

Sorry that was not it. Actually, turns out some weird engineering thing I will never understand but this works:

if (!isset($keyword)) {
 static $keyword = '';
 $keyword = $_REQUEST["${section}_search_keyword"];
}

I cannot see why this could not be one line, but that is that.

Phil

laserlight

$REQUEST["${section}search_keyword"] is an expression, and static variables cannot be initialised with (non-literal) expressions.

ppowell

I am confused, I thought an expression was something like "2+2" and not $_REQUEST["something"], that in theory is a value and not an expression.

Phil

laserlight

An expression is pretty much anything that has (or perhaps returns) a value.
(1+1) returns a value, so it is an expression.
2 is also an expression, but it is an integer literal (or constant, if you prefer).
$a, whose value is 2, is also an expression.

PHP Manual - Expressions