From PHP to PHP on PHP4.x 😕
From one PHP script I need to call another PHP where there's a need to show a single image called from a MySQL database .
pleaas help
Time to start reading the sacred texts, swami. Start with the manual. However, wouldn't this work:
$myimage='image';
$Changed_Image=changeImage($myimage):
function changeImage($image){ //do something with an $image. return $image; }