[Resolved] 4 items on one row...then another 4 etc

[darthmahon]

Hi,

Ok someone at work created the following that allows you to have two images on one line at a time...now, what I need is four on one line...hope that makes sense.

Here is the code:

<?

$RCount = 1;
echo "<table width=\"100%\" border=\"0\" cellspacing=\"2\" cellpadding=\"0\">";

while($row = mysql_fetch_array($result))
{

if ($RCount == 1)
{
echo "<tr align=\"center\">";
}
?>

<td width="25%"><? echo $row['fld_image']; ?></td>

<?

switch ($RCount) {
	Case "1":
		$RCount = 2;
	Break;

	Case "2":
		$RCount = 1;
		echo " </tr>";
	Break;
}

}

echo "</table>"; ?>

Any ideas? I tried messing around with the $RCount = 2 and putting a four, this does work but displays some funny results...

Cheers,
Chris

[LordShryku]

You'll need to tweak the concept for more than two. Try something like this

<?php
$num = 4; # Number to break at
$i   = 4; # Just a counter

echo "<table width=\"100%\" border=\"0\" cellspacing=\"2\" cellpadding=\"0\">";
while($row = mysql_fetch_array($result)) {
   if(($i % $num) == 0)  

      echo "<tr align=\"center\">";
?>
    <td width="25%"><? echo $row['fld_image']; ?></td> 
<?php
   $i++; # increment counter
}

[AstroTeg]

You might try something like this:

$count = 0;
$numcol = 4;  // number of columns 
echo '<table>';
while($row = mysql_fetch_array($result))
{ 
	if($count % $numcol == 0)
		echo '<tr align="center">';
	echo '<td width="25%">' . $row['fld_image'] . "</td>\n";
	$count++;
	if($count % $numcol == 0)
		echo '</tr>';
}  // end while($row = mysql_fetch_array($result))
echo '</table>';

Here, you can tweak $numcol to the number of columns you want to display without having to fiddle with any other code.

[AstroTeg]

LordShryku beat me to the post. The only trick with his code is there's no </tr> end tag.

[darthmahon]

Excellent! Thanks for your input, works perfectly 🙂