Code not displaying properly in HTML

Gary_Kambic

Hello,

I'm taking html code and placing it in a variable called $preview. The code below is part of the overall html code. I later print the variable <?php print ($preview);?> as part of a different html page with .php extension.

I set the variable $message="test" before I display the following code. The following is the actual show source code when the page is displayed. As you can see it's not showing "test", just echoing the php code. I'm I losing something from when it's stored in the table and then displayed? Do I need to perform some function?

I'm not sure why it's not displaying properly.

Any help would be appreciated.

Thank, Gary

TheDefender

Take a look in the manual at the [man]eval[/man] function.

Gary_Kambic

Hi,

I read the eval information and tried the following:

eval("\$newsletter = \"$newsletter\";"); [ this is line 48 ]

I received the following error:

Parse error: parse error, unexpected '<' in /usr/www/users/info/admin_client_newsletter_preview.php(48) : eval()'d code on line 3

Sounds like it's the correct statement for what I'm doing. Not sure why it's causing an error. I believe the code is typed correctly.

Thanks, Gary

biggus

Try the following:

<tr>
<td> </td>
<td colspan="2"><font size="2" font face="verdana, arial">$message</font></td>
<td height="20"> </td>
</tr>

How are you putting the html into the vartiable?

Biggus

bodzan

Like it is not being set up to read .php files as server side php but instead it outputs them like plain HTML...

Is this the only php page that you have this problem with?

Gary_Kambic

I have a text window on a web page where I cut and paste the html. The HTML is from a page with .php extension. The html in the page works fine. When I paste the html into the window then click submit to pass it to the preview page, it display the web page but without the contents of the PHP variable.

I'm using the window so I can edit the code from any location.

Hope this helps. Let me know if I can provide any additional information.

bodzan

...as TheDefender indicated i this manner:

eval($message);

What does this outputs?

Gary_Kambic

Hey thanks for the reply and sorry about the delay. I decided to go in a different direction.

I do have a question you might be able to help with.

When I have the variable:

$newsletter = "html code here";

and then send the e-mail with:

$headers .= chunk_split(base64_encode("$newsletter"));

        //send e-mail 
		mail($client_email_address_search, $clientsubject, $clientbody, $headers);

It sends the html fine. However when I try to use an include statement which has the same code, it just echoes out the code and I receive garbage.

Somehow the include is not placing the html into $variable the same it does when I just hard code as in:

$newsletter = "html code here";

$newsletter = include ("newsletters/Newsletter_HTML_Header.inc");

Thnaks for any help,

Gary