holiday trubble... with dates

[deep]

Hello!

Im building a script that needs to set a date for me. Lets say 25th every month. The problem is that it has to be a day between monday-friday (no holidays!). Lets say that I set my script date to 25th this month without knowing that 25th is a saturday (lets say it is)... how do i get the script to see that its a saturday and then flip the date automatically to the monday next week returning 27th instead of 25th?

Thanks!

[deep]

Just made this script... easier then i thought 🙂 anyone got a better one?

   if(date("w") == 0){
      $date = date("ymd", mktime(0, 0, 0, date("m"), date("d")+1, date("y")));
   }else if(date("w") == 6){
      $date = date("ymd", mktime(0, 0, 0, date("m"), date("d")+2, date("y")));
   }else{
      $date = date("ymd");
   }

   echo $date;

[rockerscc]

Basically, check the date of the month and see what day of the week it is. If it is a saturday or sunday, do whatever you want to do the following monday. should be pretty easy with a little basic php knowledge.

$i=0;

while ($i < 13 {
//format the date $i-25-2004 using mktime() function
//get the day of the week for that date

if (day of the week == saturday) {
//do what you need to do on $i-27-2004
} else if (day of the week==sunday {
//do what you need to do on $i-27-2004
} else {
//do what you need to do on $i-25-2004
}
$i++;
}

there you go. just fill in the blanks.

[devinemke]

$month_year = date('F Y');
$twenty_fifth = mktime(0, 0, 0, date('m'), 25, date('Y'));
$day = date('l', $twenty_fifth);
if ($day == 'Saturday') {$shift = $twenty_fifth + 172800;}
if ($day == 'Sunday') {$shift = $twenty_fifth + 86400;}

echo 'This month, ' . $month_year . ', the 25th falls on a ' . $day . '.';
if (isset($shift)) {echo ' So the nearest Monday is the ' . $day = date('jS', $shift);}