Retyping variable sent via POST

LazyBoy

Hello,

I have a trouble with one variable sending via POST. variable is send to script where is initialize like
$variable=(int)$_POST['variable'];
and there is problem with working with this $variable. Using formula like if($variable) and this is the problem, this $variable always look like a set, with some value. And if I remove (int) it all works as well. Don't now where is a bug.

I hope that my description is readable :-/.
Thanks all folks that tell me the truth about this :-).

Lazy

RossC0

Not sure what your trying to achieve here!

$variable = $_POST['variable']; should be fine...

Whats the (int) part for ? basically, I think if you use it you will always set a value for the $variable even if there is no value for $_POST['variable']

laserlight

Whats the (int) part for ?

To typecast to int, though using intval() might be better.

Anyway, one could consider something along the lines of

if (isset($_POST['variable'])) {
	$variable = intval($_POST['variable']);
} else {
	//set some default value for $variable, if needed
}

LazyBoy

Maybe it will be better but overall the php manual says

<?php
$num = pi();
echo (int) ($num * 10); // prints 31, not 30
?>

Note that this does the same thing and returns 31 as desired:

<?php
$num = pi();
echo intval($num * 10); // prints 31, not 30
?>
that this two syntax gave you the same result. Then I will try this one, that you gave me and will see the differencies.

Laz