$_GET + Image question

[kikki]

Hi,
I'm using $_GET['show'] to view images inside of a table, but the problem is, I see ImageNotFound default win picture inside when no any images selected..

how to view an image(notfound.jpg) When there are no images to get? Could someone guide me please?

This is the code that I use to GET images:

<tr><td width="100%" height="343" align="center" valign="center" ><div align="center"><img src="<?=$BigImgDir.$_GET['view']?>"></div></td>
</tr>

Please see the little screenshot to understand my question.

[Kudose]

if((!$_GET['view']) || (empty($_GET['view'])){
$_GET['view'] = "nophoto.jpg"
}

[kikki]

Hi,
thanks for answering.. 🙂
I've tried this code, giving me an error.. 🙁

code:
<img src="<?=if((!$GET['view']) || (empty($GET['view'])){$_GET['view'] = "images/noimageb.jpg"}?>">

Error:

Parse error: parse error, unexpected T_IF, expecting ',' or ';' in /test/grabimg.php on line 22

[klik]

if((!$GET['view']) || (empty($GET['view'])){
$_GET['view'] = "nophoto.jpg";
}

no?😕

[kikki]

Originally posted by klik
if((!$GET['view']) || (empty($GET['view'])){
$_GET['view'] = "nophoto.jpg";
}


no?😕

I've tried that code inside the <img tags... It's giving me an error:

like this:

<img src="<?=if((!$_GET['view']) || (empty($_GET['view'])){$_GET['view'] = "images/noimageb.jpg"}?>"> 

[Kudose]

if((!$_GET['view']) || (empty($_GET['view'])){
$img = "images/noimageb.jpg"
} else {
$img = "images/".$_GET['view'];
}

echo "<img src='".$img."'>";

[kikki]

Originally posted by Kudose

if((!$_GET['view']) || (empty($_GET['view'])){
$img = "images/noimageb.jpg"
} else {
$img = "images/".$_GET['view'];
}

echo "<img src='".$img."'>";

[/B]

Hi..
This giving me error.. 🙁

  <tr> 
    <td width="100%" height="343" align="center" valign="center" ><div align="center"><img src="<?=if((!$_GET['view']) || (empty($_GET['view'])){$img = "images/noimageb.jpg"} else {$img = "images/".$_GET['view'];}echo "<img src='".$img."'>";?>"></div></td>
  </tr>

Error:

Parse error: parse error, unexpected T_IF, expecting ',' or ';' in /test/grabimg.php on line 23

[Kudose]

<tr>
    <td width="100%" height="343" align="center" valign="center" >
	<div align="center">
	<?php 
	if((!$_GET['view']) || (empty($_GET['view']))){
		$img = "images/noimageb.jpg";
	} else {
		$img = "images/".$_GET['view'];
	}
	echo "<img src='".$img."'>";
	?>
	</div>
	</td>
</tr> 

[kikki]

I'm getting 🙁<b>
Parse error: parse error, unexpected '{' in /test/grabimg.php on line 21</b>
😕

[Kudose]

Try again. I had a typo.

[jannoy]

try different approach in if else

<tr>
<td width="100%" height="343" align="center" valign="center" ><div align="center"><img src="<? (isset($GET['view'])) ? echo "images/'.$GET['view']; : echo images/noimageb.jpg;";
?> "></div></td>
</tr>

[jannoy]

i have typo in echo it is not properly closed

just add this --> "

[kikki]

<tr>
<td width="100%" height="343" align="center" valign="center" >
<div align="center">
<?php
if((!$GET['view']) || (empty($GET['view']))){
$img = "images/noimageb.jpg";
} else {
$img = $BigImgDir".$_GET['view'];
}
echo "<img src='".$img."'>";
?>
</div>
</td>
</tr>

cool... This works just perfectly... 😃😃😃
Thankyou v.much guys.. Thanks to kudos, I really appreciate your help, the problem is solved now.. 😃