Seemingly Simple IF problem.

trentlott

I am trying to produce a string that will show only the checkboxes that are on. I think. I've been working on the whole project for days and I am quite worn out- this is the last thing needed, and I can't make it work!

It seems like it is very simple, but I'm not sure how to make the IFs stop. . . IFing.

if ($med1 == "ON") :
echo 'Preventec Collar: ' .$quan1 . ' ' ;
endif;

if ($med2 == "ON") :
echo 'Frontline Spray: ' .$quan2 . ' ';
endif;

if ($med3 == "ON") :
echo 'Advantage Cats: ' .$quan3 . ' ';
endif;

The med*'s are checkboxes scattered through the previous page, being clicked when the user wants that particular medicine.

med1 acts correctly, printing when checked and absent when blank, but no other IF statements will execute.

I've also tried

if ($med1 == "ON") {
echo 'Preventec Collar: ' .$quan1 . ' dd ' ;
}

With equally depressing results.

vornn

Hey Hey (in a typical Crusty the Clown voice)

This is what I use, and it works. When a check box is ticked, the variable then contains something. If unticked, it contains nothing.

Try this

if (!$tick)
{
echo $result;
}

You never know...

Hope this helps...

🙂

trentlott

How do I specify each separate checkbox?

if (!$med1)
{
echo 'Preventec Collar: ' .$quan1 . ' ' ;
}

Prints each line regardless of checkbox value.

vornn

That's the monkey...

Call them what you have called them in your form.

eg:

if (!$check1)
{
echo 'Preventec Collar: ' .$quan1 . ' ' ;
}

if (!$check2)
{
echo 'Preventec Collar: ' .$quan1 . ' ' ;
}

if (!$check3)
{
echo 'Preventec Collar: ' .$quan1 . ' ' ;
}

Hope this helps...

🙂

trentlott

No dice!

It still prints all of the lines, regardless of checkbox status!

if (!$med1)
{
echo 'Preventec Collar: ' .$quan1 . ' ' ;
}

if (!$med2)
{
echo 'Frontline Spray: ' .$quan2 . ' ';
}

if (!$med3)
{
echo 'Advantage Cats: ' .$quan3 . ' ';
}

bodzan

...
if(!isset($_POST['med1'])){
//echo thing...
}

Hope it does the trick...

kpzani

if you call all the checkboxes the same name then you can access them as an array
demo...

page 1
<input type="checkbox" id="med[]" name="med[]" value="Preventec Collar">med 1 
<input type="checkbox" id="med[]" name="med[]" value="Frontline Spray">med 2 
<input type="checkbox" id="med[]" name="med[]" value="Advantage Cats">med 3

do the same with your textboxes for quantity
<input type="text" name="quan[]" value="0">
etc

then on page 2
<?php
$medarray = $POST["med"];
$quanarray = $POST["quan"];
$nummeds = count($medarray);
for ($i=0; $i<$nummeds; $i++) {
echo($medarray[$i] . "" . $quanarray[$i] . " ");
}

hope this helps

tekky

yup kpanzi is right, i would suggest using the array method and then using if(isset($med[0]))

dont forget that most sites will using REGISTER_GLOBALS OFF so you must $med = $POST['med']; or use the$POST var the whole time

kpzani

I'm glad you agree.

but a few small points
using a checkbox array like this means there is no need to test its value only the checked items are submitted into the next page.

the sample code gets the array variables from the $_POST fields and stores them in two separate vars - $medarray and $quanarray.

as long as the sample code is followed everything should work out nicely.