[Resolved] generate html

redzzzon

Hello everyone.

I would like to have a page generated with a query statement imbeded between each row of an instance.

These instance are generated by outputting each row of a db.

Very Awosome 🙂

in bettween each instance I have a link with a
?ID=$row_info['ID'] so that I can pass it to a new VIEW of the page.

The only differance of the new page is that additional info is provided about the instance due to event on the page.

At this point if I act on the page with all the instance I get additonal info for all instance.

The event is suppose to only give additonal behaivor for instance desired.

If the explantion is long please provide keywords and LINKERS

I love this one by Mr E

When solving a problem you can think the same way in which you did when creating a problem.

Does any one know how I can get my hair to look like MR. E

Weedpacket

Sorry; is there an actual problem in there somewhere? Dunno who you mean but you could look here.

redzzzon

Below is the script. The script is good.

The isea is

query all thumbnail instance from db
display all instacnes with link to a dispalay higer pixel photo
If user chooses a thumbnail then rhe page is regenerated view with out the "for" statement (because everything is already there) with larger pixel photo inserted just above row instance of photo. and below link.
4Interface to user.

I have commented in the script below


<?php
for($i = 0; $i < $num_rows; $i=$i + 1)
{
$photo_info = mysql_fetch_assoc($result);
echo '<div id="left">';
echo '<div id="show_pic">';
echo '<a href="../photos/friends.php?page_id=friend&photo_picked=yes&photo='.$photo_info['photo_title'].'">view this photo</a>';
echo '</div>';


//this code works but the idea is to interface the pic for only for instance
//this would never work in the for loop so that is why I would like to have 
//this generated on a new page for a viewer
if(!isset($_GET['photo'])) 

{ 
echo $photo_info['photo_id']; 
echo "click on the link to see a larger image";

}else

{
echo '<div id="photo">';			 
echo 'you have picked to see'.$_GET['photo'];

/*this woul be the place a higher pixel photo would apper
 echo '<img src="../images/city_bus_stop.jpg">
however at this point if this ran the photo would appera 
as many instace there are in the db */
echo '</div>';


} 	

//this part spits out a tumbnail photo
echo '<div id="left"><img id="pic" src="';
echo $photo_info['thumbnail_location']. '">';
echo '<b id="piclable">';
echo $photo_info['photo_desc'].'</b></div>';
echo '</div>';
}

?>

Thanks Tom

redzzzon

using a condition within the for statement solved the problem.

Thanks