can i get a variable out of function

[qadeer_ahmad]

Hi,

I need to get the value of a variable which i use inside a function after calling this function i need this variabale value. But i am confuse it not working .. this is not my work but a litle example explain my need.

<?php
function addFive( $num )
{
$num += 5;
$test="this is testing";
print $test;
}
$orignum = 10;
addFive( $orignum );
print( $orignum );
print $test;
?>

as when i call the function through
addFive( $orignum );

it work and value of $test print but after this i also want this value out side of the function..

is there any way to get $test value out side the function....?

[onion2k]

 function addFive( $num )
 {
 $num += 5;
 return $num;
 }
 $orignum = 10;
 $plusfive = addFive( $orignum );
 echo "Original =".$orignum;
 echo "Plusfive =".$plusfive;

[qadeer_ahmad]

Hi.

i say this is not my code. this is only example in my codding i have to call a function which work for diffrent manner and in diffrenet conddion i need some variable value ....

if i see ur function what about u say if i declear a variable like this..
function addFive( $num )
{
$num += 5;
$test="This is testing";
return $num;
}
$orignum = 10;
$plusfive = addFive( $orignum );
echo "Original =".$orignum;
echo "Plusfive =".$plusfive;
echo $test;

i need here $test....

anyway thanks for taking intrest...

---

[laserlight]

You should declare $test global in the function.

Actually, there probably is a better way of doing what you want to do.
What exactly are you trying to solve?