[Resolved] Question about use parameters inside of include()

[sunnyside]

I would like to use some parameters inside of my include(). Here's what I found:

This format does not work:

include('../../file/edit_file.php?foo=1&bar=2'); 

But this format works:

include('http://www.mysite.com/file/edit_file.php?foo=1&bar=2'); 

Although it works, I still have question about this issue. Is there any other solution that can use parameters inside of include()?

Thank you!

[devinemke]

include('../../file/edit_file.php?foo=1&bar=2') does not work because PHP is looking for a literal filename called edit_file.php?foo=1&bar=2 which of course does not exist.

you can simply do:

$foo = 1;
$bar = 2;
include('/path/to/edit_file.php');

edit_file.php inheirits the variable scope of the parent file.

[sunnyside]

Thank you! I got it!