Plz help me (listbox problem)!!!!

[edikasim81]

My problem is:

How to maintain the list box value when user goes to editing page. About the textfield I had no problem to appear this value again.

Look at here my coding to appear value when user enter the editing page :

...
...
email = $email;
gender = $gender;
...
...
<input type="text"
name="email"
size="xx"
value="<? echo $email; ?>">//this coding success to appear the current selected value

<select name="gender" id="gender">
<option value="Male">Male</option>
<option value="Female">Female</option>
</select> // my problem here....the current selected value not appear. How to maintain this value from database

plz help me how to appear the current value when using listbox without need to select again the list value by user...

[rehfeld]

simple question-

do you ever define the variable $email ??

if you define it on another page, you will need to define it again on this page. it will not automatically hold its value on other pages.

[cezve]

clarify the problem please...

you want something like below?:

<?php

$submited_numeric_value=3; // you can set it by form; ex:1,2,3.. something numeric

$dodo=array();
$dod=$submited_numeric_value;
settype($dod, "integer");
$dodo[$dod]="selected";

php?>
<select size="1">
<option <?php echo $dodo[1]; php?> value="1111">val1</option>
<option <?php echo $dodo[2]; php?> value="2222">val2</option>
<option <?php echo $dodo[3]; php?> value="3333">val3</option>
<option <?php echo $dodo[4]; php?> value="4444">val4</option>
<option <?php echo $dodo[5]; php?> value="5555">val5</option>
</select>

[kburger]

It sounds like you just need to use the HTML attribute 'SELECTED' if it had been selected on the previous page, something like:

 <option value="Male"<?php if ($gender == "Male") echo " SELECTED" ?>>Male</option> 

or you may need to use $_POST["gender"]

[edikasim81]

Thank you to all because help me to solve this problem...