Parsing a variable to a textbox?

EPierre

Morning all,

I don't know how to solve this problem Here it is:

$price_unit = "20.45"
$qty = 'qty';
$net = 'net';
$net = $qty * $price_unit ;
as: 0<$qty<10 to parse in a textbox.
I do that :

if
($qty =0)
{
$net =0;
}

elseif
($qty =1) {
$net = $price_unit * 1;
}

elseif
($qty = 2) {
$net = $price_unit 2;
}
....
else{echo "Message...."}

In form html

.....
<input type = "text" name = "qty" value = "<?php echo $qty ?>" size = "6">
<input type = "text" name = "gross" value = "$qty * $price_unit" size = "6">

Result: qty value: 1

When I change qty to 0, 1, 2, 3, 4, etc.. gross value stay ar 20.45.

What is wrong in my code ?

Regards to all.

TheDefender

You've defined $qty as a text string.

$qty = 'qty';

Then, later you try to do mathematical calculations with it...
$net = $qty * $price_unit ;

This won't work.

Also, in your HTML form:
<input type = "text" name = "gross" value = "$qty * $price_unit" size = "6">

You do not open with PHP tags <?php ?> when you define the value.

You got a lot of cleanup work to do.

mtmosier

if
($qty =0)

Use "==" for comparison. Here you're just assigning 0 to $qty, then checking whether that value is true or false. (0 is false, so it goes on to assign 1, which is true, and gives you 20.45)