php variables

[marian]

i have this:

$variable='get'.$value.'()';
where $value='Address' and also $value changes based on user selection.

so basically what i want is, call my class's functions like this:

list($someclass)=someClass::run();

someClass has a getAddress() function and lots of other functions.

so what i want is $someclass->getAddress();

but i am using this: $someclass->$variable;
as $value changes based on user selection. but i can't get $variable to be printed; well, variable prints like this:

print $variable ==> getAddress()
but i can't get this: print $someclass->$variable;

help

[devinemke]

you have a few options here depending on the broader purposes of your code. you could simply pass the $variable to [man]call_user_func[/man] which would not require any changes to your class. or you could make your class methods a little more generic by having them take an argument that determines what function actually does. sort of like this:

function do_something($arg)
{
	if ($arg == 'getAddress')
	{
		// code to get the address
	}

if ($arg == 'getUser')
{
	// code to get the user
}

// etc...
}

again, the second option is preferable but may not work in the context of the rest of your app.

[marian]

something very interesting is happening to the way i am calling my class function:

i have this:

$value='anything user selects' eg. Address, Name, etc
$myVar='get'.$value.'()'; //so my var is getAddress()

$object = new SomeClass()

$object->$myVar //this prints $objects->""
instead of $object->getAddress() why is it doing that?

anybody knows why. oop.

thanks

[rehfeld]

try it like this

$myVar='get'.$value;

$object->{$myVar}();

[marian]

works great, thanks.