Image Uplaod

[jbachris]

I have a news manager system and on the add a news item page I want to give the user the ability to upload an image with the story.

My php is:

<?
										// form not yet submitted
										// display initial form
										if (!$submit)
											{
									?>
										<table cellspacing="5" cellpadding="5">
											<form action="<? echo $PHP_SELF; ?>" method="POST" name="theform" id="theform">
										   		<tr> 
													<td width="100" align="right"><font class="text-blog"><b>Headline: </b></font></td>
													<td align="left"><input size="40" maxlength="250" type="text" name="headline"></td>
										  		</tr>
										   		<tr> 
													<td width="100" align="right"><font class="text-blog"><b>Story: </b></font></td>
													<td align="left"><textarea name="story" cols="40" rows="10"></textarea></td>
										  		</tr>
												<tr> 
													<td width="100" align="right"><font class="text-blog"><b>Image: </b></font></td>
													<td align="left"><input size="40" maxlength="250" type="text" name="image"> <input name="upload" value="Upload Image" type="button"></td>
										  		</tr>
										  		<tr> 
													<td colspan=2 align="center"><input type="Submit" name="submit" value="Add"></td>
										  		</tr>
											</form>
									  </table>
								<?
								}
								else
								{
									// includes
									include("dbx.php");
									// set up error list array
									$errorList = array();
									$count = 0;

								// validate text input fields
								if (!$headline) { $errorList[$count] = "Invalid entry: Headline"; $count++; }

									// check for errors
								// if none found...
								if (sizeof($errorList) == 0)
								{
									// open database connection
									$connection = mysql_connect($host, $user, $pass) or die ("Unable to connect!");

									// select database
									mysql_select_db($db) or die ("Unable to select database!");

									// generate and execute query
									$query = "INSERT INTO news(headline, story, image) VALUES('$headline', '$story', '$image')";
									$result = mysql_query($query) or die ("Error in query: $query. " . mysql_error());

									// print result
									echo "<font class='text-blog'>Your link was successfully added and saved to the database. </font><a href='admin/main.php'>Go back to the control panel menu</a>.</font>";

									// close database connection
									mysql_close($connection);
								}
								else
								{
									// errors found
									// print as list
									echo "<font size=-1>The following errors were encountered: <br>";
									echo "<ul>";
									for ($x=0; $x<sizeof($errorList); $x++)
									{
										echo "<li>$errorList[$x]";
									}
									echo "</ul></font>";
								}
							}
							?>

[gufmn]

1. Do you have a question?

2. Align your code. I don't know about others on the boards, but I'm not going to take the time to read through that. You should have no problem getting help around here as there are many skilled people willing to lend a hand. But try to make it as simple as possible.

</my 2 cents>

[jami3]

Err i would help you if you just put your code inline or indent in not having lines start at one side of the page and finish the next line down. i dont have time to check it over if its like that sorry.