Why is this not possible? One $var to another file...

[darthmahon]

Hey,

Ok just wanted to find out why the following isn't possible.

I have a form that queries the database, some of this data is in DATE format. So, I have three dropdown menus - one for day, month and year.

Problem is I have a start and end date, so instead of replicating the same file twice I am using the same file, but inside a function as follows:

// $type - either day, month or year
// $date - either start or end
function insertdate($type, $date) {

// include files
if ($type == "day") {

	return include("_includes/date_day.inc.php");

} else if ($type == "month") {

	return include("_includes/date_month.inc.php");

} else if ($type == "year") {

	return include("_includes/date_year.inc.php");

}

}

Make sense? So inside my query, where I ouput all of my data into my form fields I have the following:

<p><label for="date_start_day">* Date of Event(Start):  <br />			

<select name="date_start_day">
<? insertdate("day","start"); ?>
</select>
<select name="date_start_month">
<? insertdate("month","start"); ?>
</select>
<select name="date_start_year">
<? insertdate("year","start"); ?>
</select>

</label></p>

Now lets take the year include file for instance, it looks like this:

<option value="2003"<?php if (!(strcmp("2003",  $row['date_'.$date.'_year']  ))) {echo " SELECTED";} ?>>2003</option>
<option value="2004"<?php if (!(strcmp("2004",  $row['date_'.$date.'_year']  ))) {echo " SELECTED";} ?>>2004</option>
<option value="2005"<?php if (!(strcmp("2005",  $row['date_'.$date.'_year']  ))) {echo " SELECTED";} ?>>2005</option>
<option value="2006"<?php if (!(strcmp("2006",  $row['date_'.$date.'_year']  ))) {echo " SELECTED";} ?>>2006</option>
<option value="2007"<?php if (!(strcmp("2007",  $row['date_'.$date.'_year']  ))) {echo " SELECTED";} ?>>2007</option>
<option value="2008"<?php if (!(strcmp("2008",  $row['date_'.$date.'_year']  ))) {echo " SELECTED";} ?>>2008</option>
<option value="2009"<?php if (!(strcmp("2009",  $row['date_'.$date.'_year']  ))) {echo " SELECTED";} ?>>2009</option>
<option value="2010"<?php if (!(strcmp("2010",  $row['date_'.$date.'_year']  ))) {echo " SELECTED";} ?>>2010</option>

It doesn't seem to be able to recognize the $row['']; bit when I include the file this way.

However, if I just include this file seperately and forget the function, it works ok, obviously I replace $date with start or end inside the include file.

I know it's not the problem with the $date variable, because I can echo it fine - but when combined with the $row[''] I get problems.

Any ideas?

Cheers,
Chris

[laserlight]

hmm... but where does $row come from?

Write the smallest and simplest script that demonstrates your problem.

[darthmahon]

Hi,

Ok I have attached the following file that includes a simple script that shows what I would like to do...

Hope this is ok.

Thanks for your help.

Cheers,
Chris

[sidney]

$row is not in the scope of the function.

so the function cant see it

you will have to either pass the $row to the function as a third argument

or

set the $row global or use the super global array

[darthmahon]

Hi,

Ahh ok so would the code look like this then for the function:

// $type - either day, month or year
// $date - either start or end
function insertdate($type, $date, $row) {

// include files
if ($type == "day") {

    return include("_includes/date_day.inc.php");

} else if ($type == "month") {

    return include("_includes/date_month.inc.php");

} else if ($type == "year") {

    return include("_includes/date_year.inc.php");

}

}

And then when I call the function:

<? insertdate("day","start", $row); ?>

?? Or is that completely wrong?

Cheers,
Chris

[darthmahon]

Ok just tried that, works a treat now...

Thanks for all your help guys, much appreciated as always!

Cheers,
Chris