Making Print View Button From Query

[raouleduke]

I am trying to make a print view of a page, the query changes based upon user selection, so I want to make the print view based on the query. Is this the right way to go about this, if so anyone got any ideas.

[raouleduke]

I am trying to do this.

$query = "" .$querynew. "";
print $query; 
$result = mysql_query($query);
print $result;

It prints out the query just fine but keep getting error.

Warning: mysql_fetch_array(): supplied argument is not a valid MySQL result resource

Any ideas?

[Weedpacket]

I think some of your real code would be more useful. What is $querynew and why are you tacking empty strings onto its ends? Where are you using mysql_fetch_array()? Have you used mysql_error() yet?

[raouleduke]

I am grabbing the Query from the first page, $query = printquery. querynew is this.
$querynew = $_REQUEST["printquery"];

Which would be this.

"SELECT * FROM inventory WHERE TYPE = ('U' or 'N') AND FEATURED = '1' AND ACTIVE = '1'"

Then I am just simple, making the

$query = "" .$querynew. "";
print $query;
$result = mysql_query($query);
print $result;

That is what I am asking am I going about this wrong. the print $ query looks right.