mysql_fetch_array

[FirEwAteR]

I'm wondering if there's a way to make it go through all of the rows without having a while loop? Here's the code I'm using (not that it really matters):

<?php while($i <= 14) 
		{
			$date = strtotime('') + (86400 * $i);
			$dateCheck = date('l', $date);
			while($availRow = mysql_fetch_array($availability)) {
				if($dateCheck != "Friday" && $dateCheck != "Saturday" && $dateCheck != "Sunday") { 
					if($date >= $availRow[out_on] && $date <= $availRow[due_date]){ } else {  ?>
					<option value="<?php echo $date; ?>" name="<?php echo date('YmdHis', $date); ?>"><?php echo date("F d \[ l \]", $date); ?></option>
					<?
					} 
				}
			$i++; 
			} 
		}

I need it to be able to go through the full 14 times no matter how many rows are in the database, but still check every row.

[planetsim]

Well if you could at least tell people what you want to accomplish you may get some help. Unfortunately so far I have no idea what you are trying to accomplish, besides not wanting to loop.

[FirEwAteR]

I'm trying to make an equipment sign out and make it so they cannot request dates that have already been signed out on. So it needs to post at least 14 days ahead excluding the days signed out which will all be in the database in the form of out_on for the date they signed it out and due_date for the day they need to return it