[Resolved] counting multideminsional array values

[EricC]

I'm a bit stumped on this one and going over manual is only quickening my decent into confusion.. 😉

I'm working with some an array ($tArray) that looks sort of like this:

Array 
{ 
    [0] => Array
        {
            [ID] => 104502
            [Project] => Alpha
        }
    [1] => Array
        {
            [ID] => 104503
            [Project] => Alpha
        }
    [2] => Array
        {
            [ID] => 103112
            [Project] => Corporate
        }
    [3] => Array
        {
            [ID] => 103113
            [Project] => Support
        }
    [4] => Array
        {
            [ID] => 105225
            [Project] => Support
        }

}

What I'm wanting to do is get a total of this array by [Project] so I would end up with something that would display "2 Alpha" , "1 Corporate" , "2 Support". The only caveat is that the sub-arrays in $tArray can have as few as 2 elements, and up to as many as 28.

Any insight or suggestions would be appreciated. 🙂

[devinemke]

$array = array(
	array('ID' => 104502, 'Project' => 'Alpha'),
	array('ID' => 104503, 'Project' => 'Alpha'),
	array('ID' => 103112, 'Project' => 'Corporate'),
	array('ID' => 103113, 'Project' => 'Support'),
	array('ID' => 105225, 'Project' => 'Support')
);

foreach ($array as $value)
{
	$projects[] = $value['Project'];
}

$count = array_count_values($projects);

foreach ($count as $key => $value)
{
	echo $key . ' = ' . $value . '<br>';
}

[sidney]

or

 $array=array(	array('ID' => 104502, 'Project' => 'Alpha'), 
		array ('ID' => 104503, 'Project' => 'Alpha'), 
		array ('ID' => 103112,  'Project' => 'Corporate'),
		array ('ID]' => 103113, 'Project' => 'Support')
	);


foreach($array as $val)
	{
	if(!isset($count_project[$val['Project']]))
		$count_project[$val['Project']]=0;
	$count_project[$val['Project']]++;
	}

print_r($count_project); 

[EricC]

Sometimes you can't see the forest because there's too many trees blocking your view.. 😉

Thanks for the replies, I'm going to be using a combination of both solutions!