[Resolved] Function outup isn't displaying on page..

[mband2000]

Ok, I have created a function.php file and included it into every PHP page... I'm trying to call one of the functions in the file but the output from the function is coming up blank.. here is the function code.

<?
	function Profile_Queries($querytype) {

	if($querytype = "profiletext"){
		$profileinfo = mysql_query("SELECT users.profiletext from users WHERE username = '".$kzpage."'");
		$record = mysql_fetch_assoc($profileinfo);
		$output = $record["profiletext"];
		return $output;
	}

}

?>

And here is the page the function is called from

<?
include("inc/functions.php");

Profile_Queries("profiletext");

 ?>

[laserlight]

You need to
echo Profile_Queries("profiletext");

Be careful:
if($querytype = "profiletext")

should probably be
if($querytype == "profiletext")

[mband2000]

Thank you laserlight for your help... but for some reason after making the changes that you gave me... it's still coming up blank.

I've noticed if I the code that's in the function and just placed it on the page.. it works fine.

[laserlight]

Post your updated code.

[mband2000]

<?
	function Profile_Queries($querytype) {

	if($querytype == "profiletext"){
		$profileinfo = mysql_query("SELECT users.profiletext from users WHERE username = '".$kzpage."'");
		$record = mysql_fetch_assoc($profileinfo);
		$output = $record["profiletext"];
		return $output;
	}

}

?>

And here is the page the function is called from

<?
include("inc/functions.php");

echo Profile_Queries("profiletext");

 ?>

[mband2000]

I just figured what the problem was..

I forgot to add this to the function:

global $kzpage;

it wasn't returning any results because the variable $kzpage wasn't defined in the function.