simple random image question

[deesh123]

I use Geeklog Weblog with 4images photo gallery.

A user named Lacy created a simple image randomizer that displays a random thumbnail from 4images into Geeklog. Here is Lacy's code for the randomizer:

// RANDOM IMAGE FUNCTION
function phpblock_rand4image() {
	global $_CONF, $_USER, $_TABLES;

$imgdir = "gallery";
$title_limit = 30;
$dscp_limit = 50;

// DATABASE
$rand_sql = DB_query("SELECT image_id,cat_id,image_name,image_description,image_thumb_file FROM 4images_images WHERE (image_thumb_file!='')ORDER BY RAND(NOW()) LIMIT 1");
	$num = DB_numRows($rand_sql);
if ($num == 0) {
	$rand .= '<br/><center>No images exist yet!</center><br/>';    
} else {
	$A = DB_fetchArray($rand_sql);
	$album = DB_getItem("4images_categories",cat_name,"cat_id=$A[cat_id]");

	if(strlen ($A['image_name']) > $title_limit){ 
		$A['image_name'] = substr($A['image_name'], 0, $title_limit);
		$A['image_name'] .= ".."; 
		} 

	$rand .='<table width="98%"><td width="100%">';
	$rand .='<center><a href="' .$_CONF['site_url']. '/' .$imgdir. '/details.php?image_id=' .$A['image_id']. '">';
	$rand .='<img src="' .$_CONF['site_url']. '/' .$imgdir. '/data/thumbnails/' .$A['cat_id']. '/' .$A['image_thumb_file']. '" alt="' .$A['image_name']. '" style="border: 1 solid #000000;"><br>';
		$rand .=$A['image_name'];
	$rand .='</a></center>';
	$rand .='<br>Album: <a href="' .$_CONF['site_url']. '/' .$imgdir. '/categories.php?cat_id=' .$A['cat_id']. '">' .$album. '</a>';
	$rand .='</td></table>';        

	return $rand;
}
}

For some dumb reason when I integrated 4images with Geeklog, I put my 4images directory inside of an unessesary directory.

So my address to my photo album is www.mysite.com/mypics/4images/index.php, when it should be www.mysite.com/4images/index.php

Everything worked fine up until when I tried to apply the code for showing a random image. Since I have an extra folder, the random image code sends the user to
http://www.mysite.com/public_html/gallery/details.php?image_id=8
instead of
http://www.mysite.com/mypics/4images/details.php?image_id=8

My photo album still works, I simply can't get the randomizer code to call on my directory.

What is the best way to alter the code to work with my extra /mypics/directory?

Let me know if this is too confusing :queasy:

[thorpe]

see this line?

$imgdir = "gallery";

you'll need to change that to point to the correct dir.

[deesh123]

would

$imgdir = "http://www.mysite.com/mypics/4images";

be acceptable?

[thorpe]

i would think it would be more like.

$imgdir = "mypics/4images";

why dont you try it and see? your not going to break anything :-)

[Weedpacket]

Originally posted by deesh123
would

$imgdir = "http://www.mysite.com/mypics/4images";

be acceptable? [/B]

That's not a directory, it's a URL. Use that and you'd probably end up with something like
http://www.mysite.com/public_html/http://www.mysite.com/mypics/4images

[deesh123]

Sorry guys,
After applying

$imgdir = "mypics/4images";

I realized that I incorrectly stated my problem.

Your suggestion to put my correct directory in place of "gallery" in

$imgdir = "gallery";

would work for someone who didn't have a separate directory for his 4images album outside of his Geeklog directory.

The random image code sends the user to

mysite.com/geeklog/mypics/4images/details.php?image_id=35

instead of

mysite.com/mypics/4images/details.php?image_id=35

What can I do to get it correct?😕

[deesh123]

I got it!

$rand .='<table width="98%"><td width="100%">';
		$rand .='<center><a href="[b]http://www.mysite.com/[/b]' .$imgdir. '/details.php?image_id=' .$A['image_id']. '">';
		$rand .='<img src=[b]"http://www.mysite.com/[/b]' .$imgdir. '/data/thumbnails/' .$A['cat_id']. '/' .$A['image_thumb_file']. '" alt="' .$A['image_name']. '" style="border: 1 solid #000000;"><br>';
    		$rand .=$A['image_name'];
		$rand .='</a></center>';
		$rand .='<br>Album: <a href="[b]http://www.mysite.com/[/b]' .$imgdir. '/categories.php?cat_id=' .$A['cat_id']. '">' .$album. '</a>';
		$rand .='</td></table>';  

Wooooo!

Thanks for your help 🆒