parse_str() scope

[saraadmin]

Part of my script involves conditionally calling parse_str() on a function parameter. I've just realised that the reason why the function isn't working is that, because parse_str() is called as the conditional expression in an if statement, the resulting variables only exist in that block:

if (!$force_reload) parse_str($data);

After this statement the variables created by parse_str() no longer exist (right?).

I checked the docs and apparently I can get parse_str() to store the results in array:

$data_array = array();
if (!$force_reload) parse_str($data, $data_array());

echo($data_array['name']);
etc.

but if there was a way of conditionally calling parse_str() and keeping the variables in scope it would mean that I wouldn't have to change the rest of the function.

Is that possible?

Cheers,
Richard

[Installer]

After this statement the variables created by parse_str() no longer exist (right?)./QUOTE The variables will exist in whatever scope the statement is in, whether or not you put them into an array. An "if" block doesn't define a scope.

[saraadmin]

Oops!

You're right; the actual problem was that I'd altered all the variable names with a prefix (to make sure they were unique on the URL) and forgotten to use it in the function.

sorry...