[Resolved] Need to send variable to imagecreate page

[Frederick]

I have a image resize script for creating thumbnails on the fly, but I need to pass the filename to the script. Just can't figure it out.

Resize Script: resize.php
Rendering Script: index.php

I have tried using:
<img src="Gallery/resize.php?filename=$filename">
and
<img src="<?php include("Gallery/resize.php");?>">

index.php
<?php
$sql = mysql_query("SELECT * FROM gallery WHERE catID = $catID ORDER BY id DESC") or die (mysql_error());
while ($row = mysql_fetch_array($sql)) {
	$filename = $c["catName"]."/".$row["filename"];
?>
<tr>
	<td valign="top">
		<table border="0" cellspacing="0" cellpadding="1">
			<tr>
				<td align="center"><img src="Gallery/resize.php"></td>
			</tr>
		</table>
	</td>
</tr>
<?php
}
?>

resize.php
<?php
$imgfile = "Gallery/".$filename;
Header("Content-type: image/jpeg");

list($width, $height) = getimagesize($imgfile);
$newheight = 80;
$newwidth = (int) (($width*$newheight)/$height);

$thumb = imagecreatetruecolor($newwidth,$newheight);
$source = imagecreatefromjpeg($imgfile);

imagecopyresized($thumb, $source, 0, 0, 0, 0, $newwidth, $newheight, $width, $height);

$imgout = imagejpeg($thumb);

echo $imgout;
?>

Please help me.
Thanks

[Installer]

Try this:

<img src="Gallery/resize.php?filename="<?php echo $filename; ?>" />

In "resize.php":

$filename = $_GET['filename'];

[Frederick]

Tried that before but it did not work either. Thanx anyhow.

[Installer]

If that doesn't work then your problem is somewhere else. Filename/pathname, maybe?

[Frederick]

Because the resize.php file is located in the same directory as index.php file even though I was calling it from outside of the Gallery directory, I have to set the path to the file as if I was calling it from the same directory.

It was all just addressing issues, so I was close.
So this: $imgfile = "Gallery/".$filename;
should be: $imgfile = $filename;

Thanx a lot Installer for the help.