[Resolved] searching the string

qadeer_ahmad

Hi Friends

i need to search a string which are more than one time exits in string e.g. i have a string

$string ="string my string and i want to find string the location of string ";

yes in above string u can see the word "string" comes 4 times. i want number of string and also location of string as i can do this

$text=$string ;
$pos = strpos($text, 'string');
$pos2=$length-$pos;
$length = strlen($text);
$ps_id=substr($text, $pos, $pos2);

as in $pos find the string but it find first location not 2nd,3rd,4th here i need to find all location and also number of string found.

qadeer_ahmad

the problum conunt the number of string is solved with substr_count .

now i need to see that what is string postion for all found strings.

laserlight

You probably could use regex with say, preg_match_all(), but I couldnt resist trying a solution using string functions:

function strpos_all($haystack, $needle, &$count = 0) {
	$count = substr_count($haystack, $needle);
	if ($count > 0) {
		$ret[] = strpos($haystack, $needle);
		$needle_len = strlen($needle);
		$max = $count - 1;
		for ($i = 0; $i < $max; $i++) {
			$ret[] = strpos($haystack, $needle, $ret[$i] + $needle_len);
		}
		return $ret;
	} else {
		return false;
	}
}

qadeer_ahmad

my problem is solved but i need a little more help

this is a string part of another string

<a href="/browse/post/1101493/">Record Of Lodoss War OVA - Original Soundtrack 2 (FLAC)</a>

first i seek the main string and found
"<a href="/browse/post/"
this must be same in all founds.

but i need this value.

Record Of Lodoss War OVA - Original Soundtrack 2 (FLAC)

and its always difrent.

one thing here at the end of string </a> apear.

But remember above top string is part of html page

One idea here i strat read from first found and then i found "<" i stop and the string between starting and end point is i needed.

laserlight

<?php
//suppose $str holds the string to be searched
$pattern = '/\<a href="\/browse\/post\/[0-9]+\/"\>(.*?)\<\/a\>/';
if (preg_match_all($pattern, $str, $matches)) {
	foreach ($matches[1] as $match) {
		echo $match . '<br>';
	}
}
?>

qadeer_ahmad

very very thanks my problem is solved.

qadeer_ahmad

Hi laserlight ,

A new problem but same as above now i have to find this number in string

Viewing 1 to 40 of 223

in this finding in need 223 here
'Viewing' ,' to' and 'of' is fixed and '1', '40' and '223' are variables and always in number.

i try to do this like

$str = '</td><td></td><td>
Viewing 1 to 40 of 223
</td><td><td>
<a title="View reports by Razul" href="/browse/editor/razul/">Razul</a>
<a href="/browse/post/1101493/">Record Of Lodoss Original (FLAC)</a>
</td><td>
Viewing 1 to 12 of 40
</td>';
//Viewing 1 to 40 of 223
$pattern = '/Viewing [0-9] to [0-9] of (.*?)/';

if (preg_match_all($pattern, $str, $matches)) {
foreach ($matches[1] as $match) {
echo $match . '<br>';
}
}

but it giving me nothing. i think problem is in this line
$pattern = '/Viewing [0-9] to [0-9] of (.*?)/';

Also 223 i need like a number cos i have to use it like a number.

Thanks.

qadeer_ahmad

my searching string also contain ( on the end like

Viewing 1 to 40 of 223 (

since i need to search 223 only. so for this i try to make like this

$pattern = '/Viewing [0-9] to [0-9] of (.*?) (/';

but the result again same i.e. nothing print.

Weedpacket

[0-9] will only match one single digit. To match one or more digits you need [0-9]+. (And since the "223" is a number as well, you'd match it the same way as the other two numbers, i.e., [0-9]+.)

qadeer_ahmad

i apply this pattern.

$pattern = '/Viewing [0-9]+ to [0-9]+ of [0-9]+ (/';

if (preg_match_all($pattern, $str, $matches)) {
foreach ($matches[0] as $match) {
echo $match . '<br>';
}

}

and the out put is

Viewing 1 to 40 of 223 (
Viewing 1 to 12 of 40 (

so how can i get me real finding i.e. 223 and 40.
and if i try to give

foreach ($matches[1] as $match) {
or
foreach ($matches[2] as $match) {
i found this error.

Warning: Invalid argument supplied for foreach() in d:\inetpub\wwwroot\nzbsrus\test\chstring.php on line 17

qadeer_ahmad

just i have to change it as

$pattern = '/Viewing [0-9]+ to [0-9]+ of ([0-9]+) (/';

and it solved my problem.

qadeer_ahmad

Hi,
as i am finding for the string

Viewing 1 to 40 of 223 (
like this
$pattern = '/Viewing [0-9]+ to [0-9]+ of ([0-9]+) (/';

its working nice but i seek that sometime this string comes like this

Viewing 1 to 40 of 1,023 (

so there is both possibilities i.e. '223' and '1,023'
now what is my $pattern here

Can some body guid me? I need help.

qadeer_ahmad

Hi,

i make a pattern for this as

$pattern = '/Viewing [0-9] to [0-9]+ of ([0-9],|[0-9][0-9]+)/';

but when i run this
if (preg_match_all($pattern, $response2, $matches)) {
foreach ($matches[1] as $match) {
echo $match . '<br>';
$trecord=$match;
}

}

it give me out put
1,
as it come from
Viewing 1 to 40 of 1,190

so it must be 1,190

but remember it can be 190 only.
any body help?

Weedpacket

[0-9]+(,[0-9]{3})*

In other words, 1 or more digits followed by zero or more groups each made of a comma then three digits.

qadeer_ahmad

Its working nice.