Display Web Page from Function

pothole_89

I am trying to use a function to display a web page but am getting problems..

I have contact.php where i have the include:
include("{$_SERVER['SERVER_NAME']}/includes/displaypagefunction.php");

then under my switch case default i call the function, however, this does not work... get a php error. I know its this line because when I take it out it compiles ok.
default:
displaypage("contactform.php","2.php","3.php");
break;

essentially what I want is the displaypage function to have a html template in it and then each variable to be an include file.

Below is the function html idea.. | and - are the table with the above as includes

| Title Include |

| contactform.php | 2.php |
| -------------------- |_______|
| -------------------- | 3.php |

here is part of the dispalpage function

any help would be greatly appreciated

Thanks

bpat1434

So what does your switch case look like?

If I had to change your current code, I'd ask you to do the following:
1. Enclose your code in [php][/php] tags on this board (helps the eyes)
2. Concatenate the string with the file name in it in the include() defintion.

So, your code could look like:

<?php
function displaypage($body, $sidetop, $sidebottom)
{
    global $info;
?>
<table width="100%" border="0" cellspacing="0" cellpadding="0">
<tr>
<td colspan="2">
<?php
    include($_SERVER['SERVER_NAME'].'/includes/title.php');
?>
</td>
</tr>
<tr>
<td colspan="2">
<?php
    include($_SERVER['SERVER_NAME'].'/includes/navbar.php');
?>
</td>
</tr>
<tr>
<td rowspan="2">
<?php
    if($body!="none")
    {
        include($_SERVER['SERVER_NAME'].'/includes/'.$body);
    }
?>
</td>
<?php
} // Closes function.
// Is the closing } part of your code?
// I don't see it, but I'm assuming it is.
?>

~Brett

pothole_89

Brett.. Thank your for the reply.

I will do the php tags in the forum in the future.

One further question.. how can I call this function in my php page so that it displays the code in the function

doing displaypage("contactform.php"."2.php","3.php");

returns an error.

also in the function do I have to have anything returned?

thanks

bpat1434

It depends on what you want to happen. The way you have it set up, no you don't need to return a result. UNLESS you are using the result to do more in the switch. Otherwise, you should be okay. I would have to say I'm not sure what's wrong with your switch. One mistake I run into with switches is that I forget that "default:" doesn't get a "case" right in front of it. Does your code say:
case default:
displaypage("contact.php","2.php","3.php");
break;
?

If so, take the "case" away. If not, you're 1 step ahead of me. I always forget that.

What is the error that you get? Is it a parse error, include error, warning?

~Brett