[Resolved] using "like" % in an "if" statement

[OwenTheSamoan]

I'm trying to use "like" and the wild card symbol % in an "if" statement. I have members that submit messages on my site and I want to kick them out if they use certain illegal words. This is what I am trying to do. Thanks in advance for any help.

$email ="xx xxxx xx badword xxx badword_two xx xxx badword_three xx xxxx xxx ";

<?
if ($email like "%badword%" or
"%badword_two%" or
"%badword_three%" ){

echo "You are banned from this site";

exit();

}
?>

[devinemke]

LIKE is SQL syntax, not a PHP fucntion. if you want to simply check for a string within another string use [man]strpos[/man].

[OwenTheSamoan]

Thank you very much!