How to check if an expression is false?

kevinmd88

Hi, I'm pretty new to PHP, but I'm a master at PERL, so I basically have caught on to PHP pretty quickly. 🙂 But I have a simple question that I can't seem to find an answer to anywhere. It was easy enough in PERL...

I'm basically looking for a PHP equivalent of the PERL function not(). Where if an expression is false, it returns true.

Something like this:

if (not( array_key_exists('action', $IN) )) {
   // some code to be executed
}

Any suggestions?

drag0n

might wanna check out isset() and/or empty() functions... They check for that stuff.
Also, if you want to check if it is a set, then have a ! in front..

Shai-Hulud

hi if I understand correctly you like to take an action when the key 'action' in the array $IN does not exist right?

then this is what I would do:

if (!isset($IN['action'])) {
   // some code to be executed
}

kevinmd88

Thanks a million! I completely forgot about the ! operator - it exists in PERL too. :o Heh. Thanks again. 🙂

[EDIT]
Shai-Hulud: That was just an example... I'd need to use the operator/function in more than one scenario. 😉

Thanks for your help though!
[/EDIT]