Trying to count how many Sunday's there are in a loop!

[a_j_thomas]

Hi,

What I am trying to do is to count how many Sunday's there are in a while loop. Here is the code so far:

$start = $timestamp_start;
$end = $timestamp_end;

while($start <= $end) {

$enddayname = date('w', $end);

if ($enddayname = 0) {
$counter = ($counter + 1);
}

else {
$counter = $counter;
}

$end = ($end - 86400);

}

So, basically, a day gets subtracted from the loop every time. I can echo everything succesfully, but the only thing that doesn't work is $counter

Does anyone have any ideas please?!!

Thanks

[nnichols]

In your if statement you were assigning 0 (zero) to $enddayname instead of comparing it to 0.

$start = $timestamp_start; 
$end = $timestamp_end; 

$counter = 0;

while($start <= $end) { 

$enddayname = date('w', $end);

if ($enddayname [color=red]==[/color] 0)
    $counter++;

$end -= 86400;

}

[mrhappiness]

function count_sundays($start, $end) {
	//only keep date part, throw time part away
	$start = mktime(0, 0, 0, date('n', $start), date('j', $start), date('Y', $start));
	$end = mktime(0, 0, 0, date('n', $end), date('j', $end), date('Y', $end));
	//calculate number of days betwenn start and end
	$days = ($end - $start) / 86400;
	//add day of week of start date (0 = sunday, 1 = monday, ...)
	$days += date('w', $start);
	//calc number of sundays
	$sundays = (int)($days / 7);
	//return ;)
	return date('d.m.Y', $start).'  '.date('d.m.Y', $end).'   '.$sundays;
}

echo count_sundays(time(), time() + 60 * 60 * 24 * 12);

i like this better than comparing every single day

(but i'm not sure if it works in all cases, my testcases worked)