array_pop() question

[lazzerous]

Will array_pop remove off the last element of an array if it is in itself an array?

ex:

$ar[0][1] = array("1","2","3");
$ar[0][2] = array("A","B","C");
$ar[0][3] = array("4","5","6");
$ar[0][4] = array("D","E","F");

array_pop($ar[0]);

After this, only $ar[0][1], $ar[0][2], and $ar[0][3] should exist, correct?

Thanks,
-=Lazz=-

[Drakla]

Yup.

[Weedpacket]

Wouldn't it have been faster to try it yourself?

[lazzerous]

Of course it would have, but at that point I hadn't slept in a couple of days and I was kinda loopy - sorray