radio vs textbox

zackat

Here's a snippet of a form, having two radio buttons and two textboxes.
What I would like to do is process the form when one radiobutton is selected and it's textboxed is filled.
If not the form should be shown. I would like to valid the form on input after submitting it. I tried to work on the if(!isset($_POST['submit'])){ and at all possible conditions I could think of to handle the radiobuttons and their textboxes but, I can't seem to find a solution.

Any help would be appreciated.
Thanks
Zackat


<html>
<head>
<title>Radio's</title>
<body>
<?php

if(!isset($_POST['submit'])){
	echo '<form action="',$_SERVER['PHP_SELF'],'" method="post">';

?>
<!--START FORM-->

<input type="radio" name="contact" value="address"<?php echo $_POST['contact'];if ($_POST['contact']=='address'){echo " checked";}?>>Address<br>
<input type="radio" name="contact" value="phone"<?php echo $_POST['contact'];if ($_POST['contact']=='phone'){echo " checked";}?>>Phone</font><br>

Adrresss<input type="text" name="adrText" size="25" maxlength="35" value="<?php echo $_POST['adrText'] ?>"><br>

Phone<input type="text" name="phoText" size="25" maxlength="35" value="<?php echo $_POST['phoText'] ?>"><br>

<!--SEND-->
<br>
<input type="submit" name="submit" value="send">
</form>
<!--END FORM-->
<!--PROCESS FORM-->
<?php
}
else 
{ 
   echo "ok";
} 
?> 
</body>
</head>
</html>

dalecosp

Originally posted by zackat
Hi

Here's a snippet of a form, having two radio buttons and two textboxes.
What I would like to do is process the form when one radiobutton is selected and it's textboxed is filled.
If not the form should be shown.

JavaScript...

zackat

Originally posted by dalecosp
JavaScript...

Why not using PHP?

thorpe

Why not using PHP?

because its simply a waste of server resources. back and forth between the server / client untill they get the form filled in properly.

if you did it in javascript all the work gets done on the client.

thorpe

actually, looking a little closer at your code.... i cant make much sense from it.

first you check to see if the form has been submitted, if not you show it. but in showing you check some conditions that can only work if the form has been submitted.

i cant see why you just dont display the whole form again.

zackat

Originally posted by thorpe
if you did it in javascript all the work gets done on the client.

What if javascript is turned off?
Where does validation using PHP stops and using javascript begins?

Zackat confused now...😕

zackat

Originally posted by thorpe
...first you check to see if the form has been submitted, if not you show it. but in showing you check some conditions that can only work if the form has been submitted.

i cant see why you just dont display the whole form again.

You are right, if not submitted show the form.
If submitted, $_POST vars are filled or not.
If they are filled, I'm presenting the value back when showing the form; because it's not validated as ok.

The validation:
I think it should come here:
if(!isset($_POST['submit']) || validation part not ok{
show the form again, with entered values.

Validation part:
In my thinking, something like:
after submitting the form OR
(If radiobutton address is checked AND radiotextbox is empty) or (if radiobutton phone is checked AND phonetextbox is empty)
show the form

...it sounds pretty straight forward (my opinion)

dalecosp

Yeah, that sounds straight forward.

What didn't (to me) was the original question:

What I would like to do is process the form when one radiobutton is selected and it's textboxed is filled.

....which sounds a whole lot like a JavaScript event of "onClick" or somesuch.

I probably put too much emphasis on the "when"; forgive me, please, for misunderstanding.

thorpe's point of "resources" is the major argument for JS validation IMHO, but I'm really lousy at JS, so I tend to do it all in PHP....

zackat

Originally posted by dalecosp
... so I tend to do it all in PHP....

There you go 🙂 How would you solve it?

That's my problem, I can't get the PHP syntax right. I'm a real newB. I'm getting parse errors all the time, for free...

Any suggestions?

dalecosp

Well, the usual suggestion for parse errors is "debug, debug, debug." A parse error simply means you typed something wrong. You gotta find it. The only Good News: PHP is pretty good at telling you where and why....

Debugging is a chore; it's not easy, nor fun. Most people hate it, they avoid it like the plague. It's why so little programming gets done in the hours you spend at it.

There's a thread, I think in the echo lounge, entitled "Debugging 101". It might help. Some people like to play "spot the parse errors" on the forum. You might try that.

And this one that Google turns up looks pretty good: http://www.webmasterstop.com/19.html

good luck!

zackat

Well, thought of starting a new thread....
but nah...here it goes again, or stil 😉

Here is myy not working as I want to code:

<html>
<head>
<title>Radio's</title>
<body>
<?php
$text1='hello';

$text2="you";

if(!isset($_POST['submit']) || 
	($_POST['radio']==1 && $_POST['text1']!=$text1) ||
	($_POST['radio']==2 && $_POST['text2']!=$text2) ){

echo '<form action="',$_SERVER['PHP_SELF'],'" method="post">';

//two ways of submitting the form:
	echo"check 1fst radio & type hello in 1fst textbox or"."<br>\n";
	echo"check 2nd radio & type you in 2nd textbox"."<br>\n";
	echo"if not, this form should be shown"."<br>\n";
?> 

<input type="radio" name="radio" value="
	<?php 
	if (isset($_POST['radio'])){
		$_POST['radio']=1;
	}else{
		$_POST['radio']=0;
	}
	echo $_POST['radio'];
	?>">
<input type="radio" name="radio" value="
	<?php 
	if (isset($_POST['radio'])){
		$_POST['radio']=2;
	}else{
		$_POST['radio']=0;
	}
	echo $_POST['radio'];
	?>">
<input type="text" name="text1" value="<?php echo $_POST['text1']?>">
<input type="text" name="text2" value="<?php echo $_POST['text2']?>">
<input type="submit" name="submit" value="send">
</form>

</body>
</head>
</html>
<?php
}else{
	echo "looks good , process data"."<br>\n";
}
?>

The condition

if(!isset($_POST['submit']) || 
	($_POST['radio']==1 && $_POST['text1']!=$text1) ||
	($_POST['radio']==2 && $_POST['text2']!=$text2) ){

I can't seem to get working
Process this form if first radio is checked and first textbox is "hello" or
Process this form if second radio is checked and second textbox is "you"

I hope this explains my struggle much better.

Hope to get some sort of help with my coding or thinking; NewB.

Thanks
Zackat