watermark question

[abda53]

is it possible to have a watermark but add it dynamically when the picture is called?

i have an image hosting site that i want to put watermarking on the image if the user has a free account.. but it wouldnt show if the user does not have a free account.

is this possible? im not worried about server system resources

[bradgrafelman]

Look at the PHP manual entry for [man]imagealphablending[/man]. To use this image function, you must have GD 2.0.1 or later installed on your webserver.

If you aren't sure whether the GD library was compiled with your PHP installation, run a phpinfo() and look for the "GD" section.

[abda53]

im trying out this code here which i have gotten to work, but i cant figure out how to implement it into my site. can someone help me out or give me some pointers?

<?php  

header('content-type: image/jpeg');  

$source=("2.jpg");
$watermark = imagecreatefrompng('1.png');  

$watermark_width = imagesx($watermark);  

$watermark_height = imagesy($watermark);  

$image = imagecreatetruecolor($watermark_width, $watermark_height);  

$image = imagecreatefromjpeg($source);  

$size = getimagesize("2.jpg");  

$dest_x = $size[0] - $watermark_width - 5;  

$dest_y = $size[1] - $watermark_height - 5;  

imagecopymerge($image, $watermark, $dest_x, $dest_y, 0, 0, $watermark_width, $watermark_height, 100);  

imagejpeg($image);  

imagedestroy($image);  

imagedestroy($watermark);  

?>

and here is parts of my code

  $filename = "./u/$u/$folder_info[f_id]/".$image_info[i_id].".".$image_info[ext];

$handle = fopen($filename, "r");
$contents = fread($handle, filesize($filename));
fclose($handle);
header("Content-Type: $mime");
header("Content-Disposition: inline; filename=$image_name");
header("Pragma: no-cache");
header("Expires: 0");

if($image_info[plan] = 0) 
	{
	  echo "watermarked image here";
	}
	else 
	{
	echo $contents;
	}
?>

[bradgrafelman]

Um... just paste in the image code?

Are you doing like.. "<img src='myscript.php'>" in your HTML? If so, just paste in the code!

$filename = "./u/$u/$folder_info[f_id]/".$image_info[i_id].".".$image_info[ext]; 

$handle = fopen($filename, "r"); 
$contents = fread($handle, filesize($filename)); 
fclose($handle); 
header("Content-Type: $mime"); 
header("Content-Disposition: inline; filename=$image_name"); 
header("Pragma: no-cache"); 
header("Expires: 0"); 

if($image_info[plan] = 0)  

    { 
$source=("2.jpg"); 
$watermark = imagecreatefrompng('1.png');   

$watermark_width = imagesx($watermark);   

$watermark_height = imagesy($watermark);   

$image = imagecreatetruecolor($watermark_width, $watermark_height);   

$image = imagecreatefromjpeg($source);   

$size = getimagesize("2.jpg");   

$dest_x = $size[0] - $watermark_width - 5;   

$dest_y = $size[1] - $watermark_height - 5;   

imagecopymerge($image, $watermark, $dest_x, $dest_y, 0, 0, $watermark_width, $watermark_height, 100);   

imagejpeg($image);   

imagedestroy($image);   

imagedestroy($watermark);  

    } 
    else  

    { 
    echo $contents; 
    } 

Also, how is $mime being populated? I didn't see it at all in your code.