if conditions

[goofy2feet]

This is working:

$i=0;
while ($i<5) {
$i++;
if ($i == 2 || $i == 4) {
			echo "</tr><tr><td width=\"25%\">Topic $i:</td><td width=\"25%\">$topic[$i]"; }
		else {echo "<td width=\"25%\">Topic $i:</td><td width=\"25%\">$topic[$i]"; }
}

But this produces a parse error in the 'if' line:

$i=0;
while ($i<14) {
$i++;
if ($i == 3 || $i == 5 || $i == 7 || $i == 9 || $i == 11@|| $i == 13) {
	echo "</tr><tr><td width=\"25%\">Meaning $i: </td><td width=\"25%\">$meaning[$i]</td>"; }
	else {echo "<td width=\"25%\">Meaning $i: </td><td width=\"25%\">$meaning[$i]</td>"; }
}

I can't see why the first one works but the second one doesn't...

My first post here - grateful for any help !

[laserlight]

because
$i == 11@
is a typo that should be
$i == 11

You might also use
if (($i >= 3) && ($i <= 13) && ($i % 2 == 1))

[goofy2feet]

Thanks for the more compact expression.

I can't see $i=11@ anywhere in the code I posted. (Could be an encoding problem as I am using a Japanese OS and I might have accidentally slipped in a Japanese character?)

[laserlight]

I can't see $i=11@ anywhere in the code I posted. (Could be an encoding problem as I am using a Japanese OS and I might have accidentally slipped in a Japanese character?)

Possibly, my hex editor tells me that you have a mysterious 0x81 0x40 sequence, the latter corresponding to '@' in ASCII.