Create Jpg Send To Http Base64 Or Session

[okuto1973]

I want to create and display an image.
In first.php i put code to create the image then i use <img src=""> to display it (also some other html tags for write tables etc).
I can save first the image in a file so i can know what put in "" but if i don't want to save it?
Another way is to call another php file that create the image in itself and with content type header "image/jpg" send it.
But if i want to create the image in the first.php page?
Can i put it in sessione and use it?

i have also figured out the way to pass it through http but for some reasons (perhaps magic quotes) the code transfer will became corrupted or the variables can't be big than some bytes?
How long they can be?

$data=createjpg(); //that's only an example

<img src="showimage.php?data=<?=$data?>">

i have also found some web page that say something about the base64 using this way of transfer but it works only with mozilla

$data="data:image/jpg;base64,".base64_encode($img);
<img src="<?=$data?>">

[okuto1973]

$img = "data:image/jpeg;base64,". base64_encode($data);

where in $data is stored the image created.

Now to avoid IE problems....i have see code that change the address of image show with javascript and replace it with a call to the same php file passing the image in a var _ddu

<img name="image" src="<?=$img?>">

<script language="Javascript"><!--
if (/Microsoft/.test(navigator.appName)) {
var img = document.captcha_image;
img.src = "$base?_ddu=" + img.src.substr(23);
} //--></script>

where $base is the address to the foto.php

foto.php

if (isset($REQUEST["ddu"]))
{
header("Content-Type: image/jpeg");
//die(base64_decode(substr($REQUEST["ddu"], 0)));
}

so in this way if browser is mozilla all is ok....if IE the you pass the image in variable ddu and show it with a call to the php transfering it with the right content type method.
The only problem is that for large varibales the value ddu is empty!