How to pass variable using hyperlink?

dreaddlord

Hi guys, I’m just new to php language and needs your expertise here. I wanted to add a hyperlink in a variable ($varible1) in index.php and pass the value of the $variable1 to another variable ($variable2) in another php file. Can you please show me how to do it?
Thanks a lot…

bpat1434

To pass values through the url (hyperlink) you will form it as:

http://www.domain.com/page.php?key=value

Now, you get the variable in a PHP page by using:

$var = $_GET['key'];

So, here's the gist:

<?php

echo "<a href='http://www.domain.com/page.php?id=5'>Next Page</a>";

?>

Page.php
<?php

$id = $_GET['id'];

echo "The ID is: ".$id;

?>

That will ouput:

The ID is: 5

~Brett

dreaddlord

i got an error:

Parse error: parse error, unexpected T_STRING, expecting ',' or ';' in page2.php on line 234

here's the code in index.php
<a target="_blank" href='./page2.php?variable2=$variable1'><td bgcolor=\"#99ccff\">$variable2</a></td>

what is wrong with this why am getting an error?

thanks....

kburger

Originally posted by dreaddlord
<a target="_blank" href='./page2.php?variable2=$variable1'><td bgcolor=\"#99ccff\">$variable2</a></td>

Why are you escaping some of the double quotes, but not all? Also, why are you passing $variable1 to page2.php, but passing it as 'variable2'? And why is your anchor tag not inside the <td> tag?

Assuming you're trying to echo the line above, it should be

 echo "<td bgcolor='#99ccff'><a target='_blank' href='./page2.php?variable2=" . $variable1 . "'><font face='Arial' size='2'>" . $variable2 . "</font></a></td>";

Also, your error was reported in page2.php. You'll have to post the code for that page before we can guess why you're getting a parse error.

dreaddlord

here's added information

Parse error: parse error, unexpected T_STRING, expecting ',' or ';' in index.php on line 234

index.php

<td bgcolor=\"#99ccff\"><a target="_blank" href='./page2.php?variable2=".$variable1."'>$variable1</a></td>

page2.php

$variable2 = $_GET['variable2'];
$sqldetails1="select * from table1 where name='".$variable2."'";

bpat1434

Your missing a closing ";" on an echo statement somewhere is my guess. Giving us only small bits of your line(s) don't help. If you ask for help, COPY & PASTE your code here, and put a comment as to what line is 234.

~Brett

dreaddlord

thank you guys for giving your ideas and suggestions....
i have finally made it worked...

think i got the error from here:
<a target="_blank" href='./page2.php?variable2=$variable1'>
double quotes didn't worked...

anyway, all your suggestions helps...
thanks again..

dreaddlord

i want to modify the window for the page2.php

how can i add popup window for this code?

<a target='_blank' href='./page2.php?variable2=".$variable1."'>$variable1></a>

please help me with this.....

dreaddlord

is it possible to use javascript popup window in a php codes....???

can you please show me how to do it???

Hexx

is this being echo'd <a target="_blank" href='./page2.php?variable2=$variable1'>

If so you need \"_blank\" not just "_blank"

Unless it has been changed in php5 😉

batman

It's deffinately possible.

<?php 
//what you want your colde to be here

echo "<script language=javascript>";
echo "CONTENTS OF THE JAVASCRIPT HERE";
echo "</script>";

Now, there are a couple other ways, but just give this a try and see what you get..

patsfans

I have a related question to this one.

I have a site that I'm working on where I have a global variable in the main link for affiliate accounts where the page is set up like this:

http://www.url.com/?site_id=12345

That triggers the variable $linktext2

$linktext2 = "&site_id=$site_id";

I have been able to pass the variable to every other url on the page except for the one dynamically created in this function:

function makePageLink($pageNum,$linkTitle="") { 
$pageName="page.php"; 
$link= "<a class=blue href=\"".$pageName; 
$link.= "?page=" .$pageNum;
$link.= $linktext2;
$link.= "\">"; 
if ($linkTitle != "") { 
$link .= $linkTitle; 
} else { 
$link .= $pageNum; 
} 
$link.= "</a>"; 
return $link; 
}

If I echo that value before and after the function it prints the variable just fine, just not during. Any thoughts?

Ian

kburger

This is a variable scope issue. Functions are only aware of global variables and variables they have been passed. So if you want your function to know about $linktext2 you'll need to either pass it to the function or declare it to be global within the function like:

global $linktext2;

patsfans

Originally posted by kburger
This is a variable scope issue. Functions are only aware of global variables and variables they have been passed. So if you want your function to know about $linktext2 you'll need to either pass it to the function or declare it to be global within the function like:
global $linktext2;
[/B]

That worked perfectly. Thank you kburger!

Ian