[Resolved] Cut string by last word.

[BITRU]

i have strind of 2000+ words. I need to get not more then 200 symbols BUT last word needs to be full word not part of word. So i need 200 or less then 200 symbols depends on last word lengs. Hope i make sence.

i need some like

$text = "lots lots text,lots lots textlots lots textlots lots textlots lots text";

$cuttext = get 7 symbols if 7 in midle of word take less($text);

print $cuttext // "lots" BUT NOT "lots lo"

[mrhappiness]

function cut($text, $len = 200) {
//cut string after one more character than allowed
  $len++;
  $cuttext = substr($text, 0, $len);
  if (strlen($cuttext) == $len and $cuttext{$len - 1} != ' ') {
  //last character is not a space so we have to cut off one more word
    //position of last blank
    $last_blank = strrpos($cuttext, ' ');
    //remove last word
    $cuttext = substr($cuttext, 0, $last_blank);
  }
  //trim output
  return trim($cuttext);
} 

hth

[BITRU]

Thanks//// It's what i needed. Thanks allot.