Populating a dropdown menu

[jimanderson]

Hi. Being a beginner in Dynamic Web Site development, I am rather frusterated that the following bit of code doesn't seem to do anything at all

<select name="picture" id="picture">
<option value="">Select an image</option>
<?php
// execute code if images folder can be opened
if ($imageFolder = @opendir("../images/")) {
// create an array for image types
$imageTypes = array('jpg','jpeg','gif','png');
// traverse folder, add filename to $img array if image
while (($imageFile = readdir($imageFolder)) !== false) {
$fileInfo = pathinfo($imageFile);
if (in_array($fileInfo['extension'],$imageTypes)) {
$img[] = $imageFile;
}
}
// close the stream to images folder
closedir($imageFolder);
// check that $img array is not empty
if ($img) {
// populate menu
foreach ($img as $image) {
echo "<option value='$image'>$image</option>\n";
}
}
}
?>
</select>

This code (whici is taken from the book "PHP Web Development with Macromedia Dreamweaver 2004" and is supposed to populate the dropdown menu "image"

PLEASE, HELP AS I AM GETTING DESPERATE

[Installer]

Works perfectly for me. Try adding this code to the bottom, just before the closing tag:

else {
   echo 'Directory not opened. Remove the "@" sign to find out more';
}

If that doesn't help (or even if it does), check out the link in my signature.

[jimanderson]

I was trying to use PHP while the files in question were not on the remote side but only on the local.

As soon as I put all the picture files on the remote site all worked.