Easy how to question

2koncepts

Hi,

I am trying to make each of these images in the function below a clickable link to another website or to expand the size of the image. Does anyone know how I might be able to do this?

function get_image_path($id, $p)
{

global $image_path;

$image1 = $image_path . "/" . $id . "_" . $p .  "." . "jpg"; 
$image2 = $image_path . "/" . $id . "_" . $p .  "." . "JPG"; 
$image3 = $image_path . "/" . $id . "_" . $p .  "." . "JPEG"; 
$image4 = $image_path . "/" . $id . "_" . $p .  "." . "jpeg"; 
$image5 = $image_path . "/" . $id . "_" . $p .  "." . "png"; 
$image6 = $image_path . "/" . $id . "_" . $p .  "." . "PNG"; 
$image7 = $image_path . "/" . $id . "_" . $p .  "." . "GIF"; 
$image8 = $image_path . "/" . $id . "_" . $p .  "." . "gif"; 


if (file_exists($image1))
{
    return $image1;
}
elseif (file_exists($image2))
{
    return $image2;
}
elseif (file_exists($image3))
{
    return $image3;
}
elseif (file_exists($image4))
{
    return $image4;
}
elseif (file_exists($image5))
{
    return $image5;
}
elseif (file_exists($image6))
{
    return $image6;
}
elseif (file_exists($image7))
{
    return $image7;
}
elseif (file_exists($image8))
{
    return $image8;
}
else
{

$image9 = $image_path . "/notfound_image.gif";
return $image9;
}

}

justsomeone

I'm not clear what you want to do...

Would any image found link to the same site?

Or does each individual image need to link to a different site?

The first of the above is easy, just build up the link in your function and return that.

If each image should link to a different site, then you'll need to store the relationship between each image and its website. You could do this in a text file, hard coded in PHP, but the best option is probably to use a database table.

2koncepts

All I really need to be able to do is link each picture to one URL. I have been trying to add the html link into the function, but I cannot seem to get the proper syntax to make it work.

I think I need to change this line below, but I don't have enough experience with php to make it work. I just need for it to display the image, but have it be clickable to another URL.

Current code:
$image1 = $image_path . "/" . $id . "_" . $p . "." . "jpg";

Something like this to enlarge the picture?:
$image1 = <a href=/"$image_path . "/" . $id . "_" . $p . "." . "jpg"/"</a>;

Thanks!

justsomeone

DISCLAIMER:
I don't have access to a PHP environment to try this out, but you're almost there...

Looking at your code, $image_path, would have to be a local filesystem path... something lile "/var/www/himages".

In order to create a link to an image, you would need a root URL that you can build on, something like "http://www.yoursite.com/images/"

Assuming the following values:
(it doesn't matter how closely these match what you're doing, it's just the principle of the thing...)

$image_url = "http://www.yoursite.com/images/"
$id = "10102"
$p = "x"

$url1 = "<a href=\"" . $image_url .  $id . "_" . $p . "." . "jpg\">Click here to see image</a>";

Would build upa string in url which contains a html to create a text link which reads "Click here to see image".

In the above case, the link it has built up is to

http://www.yoursite.com/images/10102_x.jpg

where hopefully your image is stored.

I don't think that's quite what you want, is it? My guessis that you want to display a thumbnail and then show the pig picture when someone clicks on it.

Do you have the thumbnails and big pictures already prepared? Is that what $p is for? I'll now assume that a $p value of "b" indicates the "big" image and "t" indicates the "thumbnail" iamge.

If that's the case, and the images are already prepared, then you would now need code something like...

$url1 = "<a href=\"" . $image_url .  $id . "_" . "b". "." . "jpg\"><img src=\"" . $image_url .  $id . "_" . "t". "." . "jpg\"></a>";

Now my assumptions are probably well wide of the mark, but hopefully this will give you a start.